68Limit-Reg

# 68Limit-Reg - LIMITED REAGENT GCHEM I LAB CONCEPT PROBLEMS...

This preview shows pages 1–2. Sign up to view the full content.

LIMITED REAGENT GCHEM I LAB CONCEPT PROBLEMS The LIMITING REAGENT of a chemical reaction is the reagent that: 1) yields the least amount of product and 2) is completely consumed during the reaction. MOLE APPROACH: 2 Al(s) + 6 HCl (aq) 2 AlCl 3 (aq) + 3 H 2 (g) Theoretical: 2 moles Al to 6 moles HCl = 2 moles A l : 6 moles HCl = 1 Al : 3 HCl 2 2 Actual Data: 3 moles Al to 10 moles HCl = 3 moles A l : 10 moles HCl = 1 Al : 3.3 HCl 3 3 therefore Al limiting reagent and HCl excess reagent Actual Data : 4 moles Al to 8 moles HCl = 4 moles A l : 8 moles HC l = 1 Al : 2 HCl 4 4 therefore HCl limiting reagen t and Al excess reagent GRAMS APPROACH: STEP 1A: Determine amount of Reactant #1 needed to completely react all of Reactant #2 STEP 1B: Determine amount of Reactant #2 needed to completely react all of Reactant #1 STEP 2: Identify Limiting Reagent and Excess Reagent STEP 3: Determine amount of Excess Reagent STEP 4: Calculate the Products yields – Using the Limiting Reagent A company manufactures AlCl 3 . They have 2,000. grams of Al and 4,000. grams of HCl.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern