68Limit-Reg - LIMITED REAGENT GCHEM I LAB CONCEPT PROBLEMS...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
LIMITED REAGENT GCHEM I LAB CONCEPT PROBLEMS The LIMITING REAGENT of a chemical reaction is the reagent that: 1) yields the least amount of product and 2) is completely consumed during the reaction. MOLE APPROACH: 2 Al(s) + 6 HCl (aq) 2 AlCl 3 (aq) + 3 H 2 (g) Theoretical: 2 moles Al to 6 moles HCl = 2 moles A l : 6 moles HCl = 1 Al : 3 HCl 2 2 Actual Data: 3 moles Al to 10 moles HCl = 3 moles A l : 10 moles HCl = 1 Al : 3.3 HCl 3 3 therefore Al limiting reagent and HCl excess reagent Actual Data : 4 moles Al to 8 moles HCl = 4 moles A l : 8 moles HC l = 1 Al : 2 HCl 4 4 therefore HCl limiting reagen t and Al excess reagent GRAMS APPROACH: STEP 1A: Determine amount of Reactant #1 needed to completely react all of Reactant #2 STEP 1B: Determine amount of Reactant #2 needed to completely react all of Reactant #1 STEP 2: Identify Limiting Reagent and Excess Reagent STEP 3: Determine amount of Excess Reagent STEP 4: Calculate the Products yields – Using the Limiting Reagent A company manufactures AlCl 3 . They have 2,000. grams of Al and 4,000. grams of HCl.
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern