77-Prob-Titration

77-Prob-Titration - ACID-BASE TITRATION (NEUTRALIZATION...

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ACID-BASE TITRATION (NEUTRALIZATION REACTION) GCHEM I LAB CONCEPT PROBLEMS Titration Equation: Acid(aq) + Base(aq) Water (l) + Salt (aq) HCl(aq) + KOH(aq) H 2 O (l) + KCl(aq) Titration Formula: Molarity ANALYTE * Volume ANALYTE = Molarity TITRANT * Volume TITRANT Stoichiometric Coefficient ANALYTE Stoichiometry Coefficient TITRANT 1) The concentration of NaOH in an industrial chemical process is normally in the range of 3.0 to 6.0 M. The process was analyzed by titration as follows: 45.7 mL of 0.500 M H 2 SO 4 was required to neutralize a 20.0 mL sample of NaOH solution. Is the molarity of NaOH solution within range ? 2) A chemist is given a 50.0 mL sample of HCl solution from a waste treatment plant and ask to determine the molarity of the sample. The chemist titrated the solution with 0.250 M NaOH. The equivalency point of the titration was reached after 37.6 mL of NaOH was added. What was the molarity of the sample ? 3)
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This note was uploaded on 07/28/2011 for the course CHM 2045 taught by Professor Eng during the Spring '10 term at UNF.

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77-Prob-Titration - ACID-BASE TITRATION (NEUTRALIZATION...

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