78-Prob-Titration-Ans

78-Prob-Titration-Ans - ACID-BASE TITRATION (NEUTRALIZATION...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
ACID-BASE TITRATION (NEUTRALIZATION REACTION) GCHEM I LAB CONCEPT PROBLEMS 1) The concentration of NaOH in an industrial chemical process is normally in the range of 3.0 to 6.0 M . The process was analyzed by titration as follows: 45.7 mL of 0.500 M H 2 SO 4 was required to neutralize a 20.0 mL sample of NaOH solution. Is the molarity of NaOH solution within range ? 1 H 2 SO 4 (a) + 2 NaOH (a) 2 H 2 O (l) = Na 2 SO 4 (a) M T * V T / Mole Ratio T = M A * V A / Mole Ratio A 0.500 * 0.0475 / 1 = M A * 0.0200 / 2 M A = 2.375 M gnificant figures “3”) 2.38 M NO ! Not in Range 3.00 to 6.00 2) A chemist is given a 50.0 mL sample of HCl solution from a waste treatment plant and ask to determine the molarity of the sample. The chemist titrated the solution with 0.250 M NaOH. The equivalency point of the titration was reached after 37.6 mL of NaOH was added. What was the molarity of the sample ? 1 HCl (a)
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 07/28/2011 for the course CHM 2045 taught by Professor Eng during the Spring '10 term at UNF.

Page1 / 2

78-Prob-Titration-Ans - ACID-BASE TITRATION (NEUTRALIZATION...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online