26-Colligative-Prob-Ans

26-Colligative-Prob-Ans - COLLIGATIVE PROPERTIES OF...

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COLLIGATIVE PROPERTIES OF SOLUTIONS GCHEM II CONCEPT PROBLEMS Colligative properties of a compound depend on quantity of solute particles not the chemistry of particles. Molality (m ) = (mole solute* i) / kilo-gram solvent where i = numbers solute particles per molecule. Freezing Point Depression ( o C): T f = – K f * m where K f ( o C/m) is freezing point constant of solvent, m (moles solute particles/kg solvent) is molality solution, and T f (– o C) is freezing point depression. Final Freezing Pt: K f = negative; T freezing = T final – T initial; T final = – T freezing + T initial. Boiling Point Elevation ( o C): T b = + K b * m where + K b ( o C/m) is boiling point constant of the solvent, m = (moles solute particles/kg solvent) is molality solution, and T b (+ o C) is boiling point elevation. Final Boiling Pt: K b = positive; + T boiling = T final – T initial; T final = + T boiling + T initial. Osmotic Pressure ( π ) = (n/V) * RT = MRT where n (moles) /V (volume) = molarity (M) and R is gas con- stant (.0821 (L-atm/mole-K) and T is Kelvin temperature (T) and units of osmotic pressure are (atmospheres). MOLALITY: 1) If 0.558 moles of molecular compound naphthalene (C 10 H 8 MM = 128.16 g/mole) solute is dissolved in 125.0 grams of benzene (C 6 H 6 MM = 73.10 g/mole) solvent, what is the molality of the solution ? molality =
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This note was uploaded on 07/28/2011 for the course CHM 2046c taught by Professor Staff during the Summer '08 term at UNF.

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26-Colligative-Prob-Ans - COLLIGATIVE PROPERTIES OF...

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