27-Kinetics-Graphical-Ans - CHEMICAL KINETICS GRAPHICAL...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
CHEMICAL KINETICS GRAPHICAL DIFFERENTIAL RATE LAWS GCHEM II LAB CONCEPT ANSWERS [A] versus Time straight line: 0 th order slope = - k ln [A] versus Time straight line: 1 st order slope = - k 1/[A] versus Time straight line: 2 nd order slope = +k 1) A straight line graph developed when ln of concentration versus time was plotted for the decomposition of 2NO 2 (g) à 2NO(g) + 2O2(g) at 436 K. If the rate constant was 2.34 /sec, what is the reaction rate when concentration of NO 2 was 1.45 M. Reaction Rate = k [NO 2 ] N ln [NO 2 ] versus time results straight line – therefore 1 st order reaction Reaction Rate = k [NO 2 ] 1 Reaction Rate = 2.34[1.45] 1 Reaction Rate = 3.393 3.39 M/sec 2) Consider decomposition of hydrogen peroxide: H 2 O 2 (l) à 2 H 2 O(l) + O 2 (g). When the ln [H 2 O 2 ] versus time was plotted, the result was a straight line. What is the rate law and what is rate constant for the decomposition if the reaction rate is 1.2 x 10 –3 M/sec and concentration of H 2 O 2 is .75 M
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 07/28/2011 for the course CHM 2046c taught by Professor Staff during the Summer '08 term at UNF.

Ask a homework question - tutors are online