hw8_sol

# hw8_sol - Statistics 528 Homework 8 Solutions...

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Unformatted text preview: Statistics 528 - Homework 8 Solutions 6.7 (a) (123.8-1.645(10/sqrt(15)), 123.8+1.645(10/sqrt(15)))=(119.6, 128.0) (b) (123.8-1.96(10/sqrt(15)), 123.8+1.96(10/sqrt(15)))=(118.7, 128.9) (c) (123.8-2.576(10/sqrt(15)), 123.8+2.576(10/sqrt(15)))=(117.1, 130.5) (d) As the confidence level increases, the margin of error gets bigger. 6.10 (a) (123.8-1.96(10/sqrt(50)), 123.8+1.96(10/sqrt(50)))=(121.03, 126.57) (b) The margin of error for the sample of 50 plots is smaller. More data provide more accurate estimate. (c) In both cases, more data result in a narrower interval due to the decrease in the standard deviation of the estimate. 6.16 n= (1.96*8000/500) 2 =983.45. n=984 is needed. 6.22 (a) From Table D, P(Z>=2.326)=0.01, so z .01 =2.326. The middle 98% of values of lie between -2.326 and 2.326 under the standard normal curve. A 98% confidence interval is (10.0023-2.326(0.0002/sqrt(5)), 10.0023+2.326(0.0002/sqrt(5)))=(10.0021, 10.0025)g (b) n= (2.326*0.0002/0.0001) 2 =21.64, so use n=22. =21....
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hw8_sol - Statistics 528 Homework 8 Solutions...

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