Q1_1030 - y =-3 y (2 + y ) 1 Math 415.01 - Dr. Huseyin...

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Math 415.01 - Dr. Huseyin Coskun - Quiz 1 - 10:30 recitation (Vutha) January 12, 2011 name.number : (1) Solve the given set of equations, or else show that there is no solution. x 1 + x 2 + x 3 = 6 - 2 x 1 + x 2 + x 3 = 0 x 1 + 2 x 2 - x 3 = 1 (2) For the given differential equation, find (a) Direction field (b) Behavior as t → ∞ and a plot describing this for different initial values showing different outcomes
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Unformatted text preview: y =-3 y (2 + y ) 1 Math 415.01 - Dr. Huseyin Coskun - Quiz 1 - 11:30 recitation (Vutha) January 12, 2011 name.number : (1) Show that v 1 ( x,t ) = e 4 t cos 2 x and v 2 ( x,t ) = e 1 t sin x are solutions to v xx =-v t (2) Find the solution to the initial value problem y + 3 y = t 3 e-3 t , y (0) = 3 1...
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This note was uploaded on 07/26/2011 for the course MATH 415 taught by Professor Costin during the Spring '07 term at Ohio State.

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Q1_1030 - y =-3 y (2 + y ) 1 Math 415.01 - Dr. Huseyin...

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