SolutionHW5-SP11

SolutionHW5-SP11 - Solution SP 2011 Homework Assignment #...

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Solution SP 2011 Homework Assignment # 5- Chapter 3 and 4 Dr. Goel 3.68 3.82
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3.86: 4.2 d, if k>-5 and k+4<5, i.e, -5<k<1, then 4 1 ( 4) 0.4 10 k k P k X k dx  
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If k<-5, then 4 5 19 ( 4) 10 10 k k P k X k dx   If k>1, then, 5 15 ( 4) 10 10 k k P k X k dx   4.4 (a) It is easy to see that ( , ) 0 fx , so for this function to be a genuine pdf, we need to show that 2 2 2 2 0 1. x x e dx Now, let us make a change of variables, 2 2 2 / 2 ( / ) t x dt x dx 
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SolutionHW5-SP11 - Solution SP 2011 Homework Assignment #...

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