Project3ans - Answers for Project 3 Minitab output for 95...

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Answers for Project 3 Minitab output for 95% confidence interval for p = the true proportion of all truck drivers who suffer from sleep apnea (Exercise 7.45, McClave’s text): Test and Confidence Interval for One Proportiom Test of p = 0.5 vs p not = 0.5 Sample X N Sample p 95.0 % CI Z-Value P-Value 1 124 159 0.779874 (0.715473, 0.844276) 7.06 0.000 QUESTION 1: Based on the data in Exercise 7.45 of McClave’s text, what is the estimate for the proportion of all truck drivers who suffer from obstructive sleep apnea? On the output, the value under “Sample p” is the estimator for the true population proportion, p . Thus, ˆ p = . 779874 is the estimator for the true proportion of all truck drivers who suffer from sleep apnea. QUESTION 2: What is a 95% confidence interval for the proportion of all truck drivers who suffer from obstructive sleep apnea? On the output, the interval under “95.0% CI” is the 95% confidence interval for the true population proportion, p . Thus, 95% confidence interval for the true proportion of all truck drivers who suffer from sleep apnea is (0 . 715473 , 0 . 844276). QUESTION 3: What is a 90% confidence interval for the proportion of all truck drivers who suffer from obstructive sleep apnea? How does this interval compare to the interval that you obtained in your answer to question 2? Output for 90% CI: Test and Confidence Interval for One Proportion Test of p = 0.5 vs p not = 0.5 Sample X N Sample p 90.0 % CI Z-Value P-Value 1 124 159 0.779874 (0.725827, 0.833922) 7.06 0.000 Thus, 90% confidence interval for the true proportion of all truck drivers who suffer from sleep apnea is (0 . 725827 , 0 . 833922). As expected, the 90% confidence interval is shorter than the 95% interval obtained as the answer to Question 1.
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