homework2sol - Ke y for AST3018 H MW 2 31 Points Leah Simon...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Key for AST3018 HMW 2 31 Points Leah Simon October 1, 2009 2.1 (3 pts) Using the equation: v esc = 2 GM r (1) and the values G = 6.67 × 10 11 m 3 /kg/s 2 , M = M Sun = 1.989 × 10 30 kg, and r = Earth’s Orbit = AU = 1.496 × 10 11 M we get v esc = 4.21 × 10 4 m/s. Using the equation: v orbit = GM r (2) We find v orbit = 2.98 × 10 4 m/s. Therefore, v esc /v orbit = 2 . 2.2 (3 pts) Using the equation: F = GMm r 2 = mg (3) we find there is a relationship such that M Earth R Earth 2 = a M obj R obj 2 (4) Where a is a constant relating g object to g Earth . Therefore, using values taken from the book, we find a.) g Moon = 0.17 g Earth b.) g Sun = 27.9 g Earth and c.) g Jupiter = 2.54 g Earth 2.3 (3pts) Use the equation W = mg where W is the weight in Newtons, m is the mass in kg and g is the gravitational acceleration on Earth, a) on Earth W = 75 kg * 9.8 m s -2 = 735 N b) on the Moon, recall from previous question g Moon = 0.17 g Earth so W = 75 kg * 0.17 * 9.8 m s -2 = 121 N
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 07/28/2011 for the course AST 3018 taught by Professor Lada during the Fall '08 term at University of Florida.

Page1 / 3

homework2sol - Ke y for AST3018 H MW 2 31 Points Leah Simon...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online