This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Let us check (20, 21, 29) is a Pythagorean triple or not by using Pythagorean Theorem a^2 + b^2 = 20^2 + 21^2 = 841 c^2 = 29^2 = 841 Since a^2 + b^2 = c^2 so (20, 21, 29) is a Pythagorean triple. If we take m = 5, n = 3 a = 2mn = 2*5*3 = 30 b= m^2  n^2 = 5^2 – 3^2 = 16 c= m^2 + n^2 = 5^2 + 3^2 = 34 Let us check (30, 16, 34) is a Pythagorean triple or not by using Pythagorean Theorem a^2 + b^2 = 30^2 + 16^2 = 1156 c^2 = 34^2 = 1156 Since a^2 + b^2 = c^2 so (30, 16, 34) is a Pythagorean triple. If we take m = 6, n = 2 a = 2mn = 24 b= m^2  n^2 = 6^2 – 2^2 = 32 c= m^2 + n^2 = 6^2 + 2^2 = 40 Let us check (24, 32, 40) is a Pythagorean triple or not by using Pythagorean Theorem a^2 + b^2 = 24^2 + 32^2 = 1600 c^2 = 40^2 = 1600 Since a^2 + b^2 = c^2 so (24, 32, 40) is a Pythagorean triple. Reference: Bluman, A. G. (2005). Mathematics in our world (Ashford University Custom Edition). United States: McGrawHill....
View
Full Document
 Spring '10
 BLUME
 Pythagorean Theorem, Pythagorean triple, m^2

Click to edit the document details