{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

math_week4_assignment

# math_week4_assignment - Let us check(20 21 29 is a...

This preview shows pages 1–2. Sign up to view the full content.

Project # 4 Pythagorean triples are triples of the form (a, b, c) for which a^2 + b^2 = c^2. A formula that can be used to generate infinite number of generating Pythagorean triples is: a = (2mn); b= (m^2 - n^2); c= (m^2 + n^2) where m and n are positive integers and m > n. Let us develop five Pythagorean triples: For m = 4, n = 3 a = 2mn = 2*4*3 = 24 b= m^2 - n^2 = 4^2 – 3^2 = 7 c= m^2 + n^2 = 4^2 + 3^2 = 25 Let us check (24, 7, 25) is a Pythagorean triple or not by using Pythagorean Theorem a^2 + b^2 = 24^2 + 7^2 = 625 c^2 = 25^2 = 625 Since a^2 + b^2 = c^2 so (24, 7, 25) is a Pythagorean triple. For m = 4, n = 1 a = 2mn = 2*4*1 = 8 b= m^2 - n^2 = 4^2 – 1^2 = 15 c= m^2 + n^2 = 4^2 + 1^2 = 17 Let us check (8, 15, 17) is a Pythagorean triple or not by using Pythagorean Theorem a^2 + b^2 = 8^2 + 15^2 = 289 c^2 = 17^2 = 289 Since a^2 + b^2 = c^2 so (8, 15, 17) is a Pythagorean triple. If we take m = 5, n = 2 a = 2mn = 2*5*2 = 20 b= m^2 - n^2 = 5^2 – 2^2 = 25 - 4 = 21 c= m^2 + n^2 = 5^2 + 2^2 = 25 + 4 = 29

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Let us check (20, 21, 29) is a Pythagorean triple or not by using Pythagorean Theorem a^2 + b^2 = 20^2 + 21^2 = 841 c^2 = 29^2 = 841 Since a^2 + b^2 = c^2 so (20, 21, 29) is a Pythagorean triple. If we take m = 5, n = 3 a = 2mn = 2*5*3 = 30 b= m^2 - n^2 = 5^2 – 3^2 = 16 c= m^2 + n^2 = 5^2 + 3^2 = 34 Let us check (30, 16, 34) is a Pythagorean triple or not by using Pythagorean Theorem a^2 + b^2 = 30^2 + 16^2 = 1156 c^2 = 34^2 = 1156 Since a^2 + b^2 = c^2 so (30, 16, 34) is a Pythagorean triple. If we take m = 6, n = 2 a = 2mn = 24 b= m^2 - n^2 = 6^2 – 2^2 = 32 c= m^2 + n^2 = 6^2 + 2^2 = 40 Let us check (24, 32, 40) is a Pythagorean triple or not by using Pythagorean Theorem a^2 + b^2 = 24^2 + 32^2 = 1600 c^2 = 40^2 = 1600 Since a^2 + b^2 = c^2 so (24, 32, 40) is a Pythagorean triple. Reference: Bluman, A. G. (2005). Mathematics in our world (Ashford University Custom Edition). United States: McGraw-Hill....
View Full Document

{[ snackBarMessage ]}

### Page1 / 2

math_week4_assignment - Let us check(20 21 29 is a...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online