Math_211_Take_Home_Exam_2

Math_211_Take_Home_Exam_2 - Student Number Math 211 Take...

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Unformatted text preview: Student Number Math 211 Take Home Exam 2 Andy Callison, Travis Marshall, Karen Repko, Angela Dobbins 1. + 1 2 3 4 5 6 1 2 3 4 5 6 10 2 3 4 5 6 10 11 3 4 5 6 10 11 12 4 5 6 10 11 12 13 5 6 10 11 12 13 14 6 10 11 12 13 14 15 a. 1 4 1 3 5 seven b. 3 4 1 3 5 seven + 2 4 2 seven _-2 4 2 seven 1 0 1 0 seven 1 6 3 seven Part (a) from right to left reads: 5 + 2 = 10, 1 + 4 + 3 = 11, 1 + 4 + 2 = 10. Part (b) from right to left reads: 5 -2 = 3, and since we dont have enough to subtract 4 from 3 in the 7s column, we will decompose (borrow) from the next column (the 49s column) making it 13 4 = 6. Finally, 3 2 = 1. 2. * 1 2 3 1 1 2 3 2 2 10 12 3 3 12 21 2 0 four a. 1 2 3 four b. 3 four ) 1 2 0 four _*__2 four _- 1 2 four 1 1 2 four 0 0 Part (a) from right to left reads: 3 * 2 = 12, 2 * 2 + 1 = 11. Part (b) from right to left reads: 3 goes into 12 2 times. We multiply 3 * 2 = 12 and write 12 underneath and subtract to get 0. 3 goes into 0, 0 times with no remainders. 3. (A B) C + A B C A C A B B A B C C B C C Since we are shown an expression using subtraction, but only given a table using addition, we will need to use the Inverse Relationship of Addition and Subtraction to simplify the expression. If A + B = A, then A B = A. So, when substituting (A) for (A B) the expression becomes (A) C. Then, if C + C = A, then (A) C = C. So we can evaluate the expression as (A B) C = C. 4. a n = 4( n + 1) This shows the structures increasing in sort of a pinwheel fashion. 4 sides with the number of blocks per side equal to the structure number plus one....
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This note was uploaded on 07/27/2011 for the course MATH 211-212 taught by Professor Spindor during the Spring '11 term at Mt. Hood Community College.

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Math_211_Take_Home_Exam_2 - Student Number Math 211 Take...

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