Math 211 Take Home Exam #1
Andy Callison, Travis Marshall, Karen Repko
1. a.
A
∪
B = The union of sets A & B
A
∪
B =
{
a,b,c,d,e
}
b.
A
∩
B = The intersection of sets A & B
A
∩
B =
{
b,c
}
c.
A
∩
B = The intersection of sets A & C
A
∩
B =
{}
d.
(B
∩
D)
∪
(A
∩
C) = The union of sets formed from the intersection of sets B & D and
also the
intersection of sets A & C.
(B
∩
D)
∪
(A
∩
C) =
{
e
}
2.
If n(F) = 71 and n(G) = 53, then the union of sets F & G would be n(F
∪
G) =
124, but since it is shown that the intersection of sets n(F
∩
G) =27, we know
that 27 of the elements are similar, thus we will not count them twice; leaving
us to subtract 27 from 124 giving us:
n(F
∪
G) = 97
3. a.
This is a geometric sequence since there is no common difference shown.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
To find the formula, you need to find the common ratio. Dividing a number in the
sequence by the number preceding we find the common ratio to be 0.7. (1.4/2=0.7)
Now we use the first number in the sequence, along with the common ratio and
enter them into the formula for geometric sequences to end up with:
a
n
= 2 * 0.7
(n1)
b.
This is an arithmetic sequence since we can see that it has a common difference
of 1.2.
This is the end of the preview.
Sign up
to
access the rest of the document.
 Spring '11
 spindor
 Math, Sets, Geometric progression, common ratio

Click to edit the document details