rmamcp

rmamcp - Rolling motion, angular momentum vector and cross...

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Rolling motion, angular momentum vector and cross products Now, for the physics version of Nascar racing. The entries in this marathon are: a particle, hoop, cylinder, and sphere. These objects are to race down an inclined plane. Neglecting friction, mechanical energy of the earth-object (particle, hoop, cylinder, or sphere) system is conserved. Our textbook proves the kinetic energy of a rigid body consists of both translational and rotational kinetic energy, K tot K transl + K rot = ½ m v 2 + ½ I ϖ 2 , where v is the speed of the center of mass of the object and I is the moment of inertia about the center of mass of the object. Assuming the objects start from rest a height h above the horizontal tabletop then E i = mgh and E f = ½ m v 2 + ½ I ϖ 2 , and E i = E f along with v=r ϖ will decide the value of v at the bottom of the incline and therefore, the winner. So, which object wins the race? Angular momentum and torque: revisited
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This note was uploaded on 07/29/2011 for the course PHY 2048 taught by Professor Chen during the Spring '08 term at UNF.

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rmamcp - Rolling motion, angular momentum vector and cross...

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