105-19991-MT1 (2) - DEPARTMENT DF PHYSICS PHYS 105 FIFIST...

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Unformatted text preview: DEPARTMENT DF PHYSICS PHYS 105 FIFIST MIDTEHM EXAM mg M[NUTE5 Nov. 2D. 1999 (D MIDDLE EAST TECHNICAL UNNEHSIT‘I’ TIME: TDTALEHADE I956 Fill in this art with I I] not 1with i ncil: LnsT NAME FInsT NAME. srun. ND. sroNnTuuF. seer. IUHADES.‘ * There are 4 elassical type problems. ~fou must solve all of them. Calculator not permitted. - Do not ask proctors any question about the problems. Read. understand and solve. * The shape of the solution of each problem must be shown clearly in the space provided. Numerical answers must be given with correct 5] units and 5! unit symbols must be used only. Write your answers in boxes provided. otherwise your answer will not be considered. PROBLEM (1} {as points} A hot-air balloon is ascending {rising} vertically at the constant rate of 10 ms and is 24:] rn above the ground when a key is dropped from the balloon at time r: G. Take the direction of motion along the vertical 3; axis. 1rvith the positive direction ot‘y upward. [g = 10' misfit ta]: Find the maximum height H from the ground reached by the key. 4 3| . | Ext-virilth in “her. gram-rid; 15*- M heap: i i 1!: .J;=+|¢.-.1i5 | ii = + atom -‘ ' “’1' {fry-near 5 L5 = J | a ‘L __ I LT a a; +1.9 {:1 :1.) SI :4fiSF‘E-fl L) GTEHrd : iGJ'E—Gfl 'i' qgfla - his = ass-a 21' a J Phys 1135 First Midtcn’n Page 1 Nov. 11]. 1999 {b} Find time I at which the key hits 111: ground. hhHuL 4-9 Mjwudfld 3 )5? WEE-fl Lr‘:+mmh. a ,L *’- gz-l-E'H‘flm '5! fia+Uj+lai a: a: m +w+ w 3| :3 E-tL—Iut—l‘+fl=fl t. ._. __E 4:. —2t - “+3 ‘ ‘3 t t His—“hm -1 L" J A :4i? .r t __ g .2. {:3} find th: position J: of lhe key WW 5 s after being released from the hallnnn. t=55 1L -+LFJt,+-1—fi11_1 :. E ‘31 JD a 2' l 3 ' 3:3.“13+EL01fi}—5f5} : 3+: + 5:: — :19 :1E5 M {d} In unit-vecth notation. find the vclflcity v1.3; at the. Ray {H} mm} 5 s after being mlemd fmm the: balloon. km} A -—H H “" t=53 d Una—UKG+LEE—VLG*LEE {3 : rad-1 j 7* =3 fa :JF5u:+fltd——abr=t‘£"3t Um : ,9 am?) _h A :- L'H} M'll‘: Phys 105 Firsn Midlcn-n Page 2 NM. 23. I??? PRGBLEM {I} {25 points) Two blocks. in] = 3.0 kg on the inclined plane (6 = 37"} and m; = 5.0 kg on the horizontal plane are connected by a light cord over a frictionless pulley. A force F = 5!] N is acting on m: in a direetion making 53" Iliritli the horizontal as shown. The coeffieients of the static and the kinetic frictions for both blocks and surfaces are as = 0.3 and is“ = {12. The system is initially at rest. {1:115 37"” = Sin 53* = 118, sin 37'" = :05 53" = 115, g =1flI misl} {a} li‘the system is released from rest, how does it behave? Explain briefly giving argument to support your answer. gait dogs net I Asses-«E “ii-vi M 93ele lend/ugh meme Lu ‘qu pupil-lee dame Lil-Mia le‘lCi-Fi fiqi'Cii .3: 519ng is + .- ‘Lfi = Fmfig‘: Eats-talflfi'hl H w EH ‘Me swim Iii — mess: 1F“ = migmss' 1-in-er : Ii rfigi i s- : lg +{i-ihlmlgmsss"; + [G-i-Hr‘flgg— Fe :13 + iii-Ellen‘s + ifl-iilEe—ilo} : [‘fi 4' Tr'll‘l'B 3 Rig-EH Wire. '2 F... ‘7 2. F. “hue sugsiew 5W1” +0 Wfi w Tfiiflfldfiew {Iii Flnd lhe acceleration o of the blocks. ErMG't-arb-ibu: 1F=Mfl —:I ‘51: We; M seals-lieu “finalist-j we .ittw‘i Lei-1; LEMMA firm.- ,_,,'_,.I W Letleulam. -, ii: = s + iii-sires} +fl-2-i5u’r—‘ifil Bil—F :1 lila- _:F_ Wild-ML = [3+ E-|.s +1: iii-3N J “Hus” 8* Ans; is: E]. Efimfll {ch Find the distance d travelled by ml in 21] s after the system being released. -'I.._,.'|' IL Us=3 I=Ka+bfli+i~91L—ha:'lifli t -; 9:0-55Wl5i {legroeelflij: slam l’hgs “15 first Mid1cn‘n Page 3 Nos. ill I??? PROBLEM {3] {25 paints} A man is riding en a flatear travelling with a constant speed of IE mi's. He wishes to threw a hall thmllgh at 51311011”! hflfiP [fixed en the ground] 51} m above the height of his hand in such a manner that the hall 1wiii he meving heriiszintalljrr as it passes threugh the hnep. He throws the hall with a speed OH 1345 ntfs with respect to himself. [g = 10' W52} {a} What must be The venical component of the initial veieeity ef the bail? Variimi Hw+bfiljut reflex—Hug 4-9 ‘i‘m. firms in ii 9‘44 FE'QHHIEL +0 Mf1fl+fiflf will [TE M ng-t- Hts-Le. fw- ‘fw. hell I); : QT = #3:."iflflii'riz' "He “‘5' s ‘5’” Uh'fL ‘ Jail + “I (Tye) J : [121:FE-C3ir5) Ans; my: ‘ffl' “f5. Eh} Haw many Secends after he threw: the hall 1r'Itiil it pass through the heap? \IJEPH Lei! mam .' £1:ng +0.,t o 2 te—tet t = '1 3 Phys 1435 First Midwn‘n Page 4 NEW. 2|}, 1999 {e} 1Illt'rite the initial velgeilx 93.; of the hall {B} relative to the ground {G} in terms of the unit vectors? _.._'-.I --—5 h“ t lcdcaw Wag. : We: "i" fife-:6 C If EEG-11239159 LJ‘ : LEE 1 + E53 :; [Haiti "4“: LL LJ A II T" Jr A U, J “IL-EEC; '— U‘Etjxl + Jam-it: E1 - r “t _ " I24? Ueeig - that: “SHE " Vet; ' éL +161} + A “I 2 +1 A $12.; = “health 4" mi 5 {at DJ An$.:93.5 ={lE-C 'l'lajfimllfi PROBLEM {4} [25 paints} Twe mama m. = 4 ltg and :11; = 5 ltg are attached by a rape ever a frietienless pulley, as shown. Mass m1 retetes with the pulley in the 1: plane while mass m: staying at rest on the axis of tfltallfln.Tht len 1h 91“ the rope from the pulley 1e mass m. is L 243,131. Neglect the mass 01' the pulleyI and rape. {g = lfiTnfsTj“ I'M {3} Find the tensifln T'm the rape. K5) Fare Mme-m. m1”. ZF=O Tagazo T: 5-3 H Phys. E95 Firsl Midlerm Page 5 New. 29. I999 {hj Find angle 9. {ms 3‘?“ = sin. 53” = 0,3, sin 3?“ = mg 53¢- : {L451 sin 300 = mg me 2 351.305 3am: = sin fit)“ a fit; sin 45* = ms 45” a fig] Ermaga ml: ZFT=O fl Tamfi=m,g_ ' :nfiE—rB—g- J " LIT - .'. B: 5?: [a] What is v, thc speed uf mass #1.“? EN mam ml: EFL: MID. . l ' Tmem‘T? -—-—:u LFL: LEE—fig— . q. (ggyfa-EECZ‘Jffl-E} £335.; _ 3, r - Ur- : __—————-'—"__"__F _ t: _' Li I : 3 “I5 Ans.:v= 3Mf’5 lid} What is N, the number of rotations of mass MI] in It] 5? {Take .1 = 3} Period T = 1W- ; Ln“) = H *5 Phys m5 F'Lm Midterm Page t3 Nov. 2!}. 1999 ...
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105-19991-MT1 (2) - DEPARTMENT DF PHYSICS PHYS 105 FIFIST...

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