112-20012-MT2 - QJ. A par-11'le {mung-1 I11 and clmrgeq is:...

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Unformatted text preview: QJ. A par-11'le {mung-1 I11 and clmrgeq is: pmjeflfid with n L-elw'lly an. inn} :1 unifnrm ermuic field L1!" E and length I. . . . _ _ _ E. as ihfl-WH m The figum. Lem-mg “HS. held It EntBTE-inlu IL I. T—AE a t a I unifnrm mflgnutiu fi¢lal m" fl and fnlhm-H a circular path: “- "l " 'E'T “ ' _ '" "TE 1 6 w a "-'-r-altuh[‘mriI1-Ia lrnt it". ‘3 un1III1 aIrILu. 11:. | I1 3 “53" I“ll I '1' .4; a. 21' a 11 . _ _ l.- C 4:} What is rho Sign ui'lhc charge q [1' the: particlu'.’ Explain hriufly 1mm ynu dawnninfld it. ' ql is fle-Egi'mv:. T312. -._E'F.:-w:_,r.-U :5»; {3L mavimg chmjuk Ifmi'it‘sg :flfl DI- MH.EHE£[£ E11345 {5- C'IE EEG‘KJH E). A??HLJ¢-nfl flu: H'a‘l-wiJhmmd huEtJ 5U:"n a. E'iEJE'IEC-‘I‘i'ififi 'm flu; Wagne‘ri: ‘Efafié 11E fiiu’tw Awacbim Emeline-,0}th “Hawk; qt '15 figgafiiwa. 1' In} Lialuuinlc: :hu spud ufllm paniuie as H enlers irflu the magmctiu finld. q in 1mm: a’r‘vhquF undLJ H ‘15 HE : H151. ‘3 - Fr: vii—'3 +1111— qgi=flfll+ '1 E L- M M u'l Find the difitlflflfl 31 cf pU-iTlI P [’mm the Edge Inf magmatic field regiurlLJ III terms :1!" I.',,.q:m.E_E and L} m'L-E 515 mfli=fiV3 "95‘ 'Kr 1J1 Find lhl: lime tlml Ihe [Jami-.11.: traveled 111 L11: magnum fitJd mgmn. 1' [n lrmns ufqm and I3.)I _ "IT"!- Ardmyh Hr wants. 5E1;— _ 1,1. 1 H J'rrwmks nut-Ha «tau-LB ul m -n-- 1T*- H EL. MTT 4:: _5_ : 7%. :E-‘Tfi m -f:-r '1} 'W {17‘ 35 (1.1. fl. Imp nffii'ire {11" h = 5.1} cm 1'5 placcd in the plum: {11" B' Imi’rhml magnth fiald nl' B = ll} T us: _5hm1rrr in th: figure arm qnn'ies Jl current [1H = 3J1] H. in the grit-En dirtntiun. 3} Calculate 1.11:.- rnngn'ttutlt fifth-,1 threes {m IIIE'aegm-ants M3, E3123. CD, HIT, mm] l-Ie‘t. fihnw their dirmtftinns an the figure. E: I vii) n th=lfifil§ifltflb 5:3 (I; a . n 513.. nan-5.2.313: .1: 51531.5 H EHqGEE-i—r-s: L -1. Fan=I€-fi%%gfli§_q,firku N FDEHD '1' . 1494 Pan: IE3?- = titanic» Max 5:: c. 1. ~ u} [Tuipulute Lhc- inflgnitudt u’r'thu mrque acting ml the lung. Slum I'ts dim‘ctiml. -—"| = Lin-“1‘6 3-43.13 :2 'IBKEJIIEL: 1.1Lfiq-‘LD H-‘M 1;:an a=figm¢ 5559; L ‘L 13 ,_, . =1I'3-5LUD N “.1 _.r '1“. Q}. A lm'nflT cumin] cable cuns'rsts afnn inner win:.'3urruw1ded b3.- .1. cantata-1'1; uyilndriqfiai chuductar tube 111' innermdius R and mum“ radius 33. Th: 'n-mer wire carries a cum-n1 L. inward and “1.: cylindrical rubs cumin L1H: same currcnl: L, outward. diatfibuted uniformt} acmsa iIs arc-ss- smann . If Ste the figure]. I1: Detemtmu the magnitude nftlle magnetic: field in the cylindncal Luhc, .11 :1 diilflflcfi r fml'r: the Hi5 when: R4: r ‘t 2R. an d a155, lmr FE; L - LE 51}; . ,uol‘r. [11,3 h] [jam-nun: :Iu: mugllitudl: ur'thu mngncstc field outside 1hr: CJL‘IE. HI .1 (haunt? r from thu Luis whth r fill. 31 HI“ : fifi- (IE-IC- io-sj T559 cylindrical Tube. Explain your man-n.1- Ian-effi- ‘F “‘5 '7' ' r '1 III .— l . ELF-“16M? 3 Ex? M W 01% r'? Fifi! cl What is me magnitude nl'ihc mailman: three on [he inner 1.x in: due Tr. I'm: burr-m1 an the =; é EA?=O) Ill-II. A win; nf IErLgth L is Funnud inn- a circular rlng. IL'JR pfqmfl nn The fil-yplfil‘lfl and earring: u currunl | in the clockwise fiiruullqn m; ginwm irt th' figuru. "1-le 'llfl'.‘ flim‘finvnrt Luv; :0 dwivc EJ'H: equalion for H11: The magnetic field-.31. U11: ppinl P. The center nt‘the ring. I: In ten-n5 nfcnnslamrs. Ifmd L}. {Hwyit In unin'ectm nutatiun. Alan shnw ‘13 direcgiun an m: figurp. £=M§EE Hatch) “HT TL 3 ALL” M: :gigfig = .“ claw ” mt P} 3+ I 1‘ Lm R53 .113“ A». .d l— A:: .EEE "L3 ZHQHJJ J Rfigfi 3 fl i; L [1} Now Ihe 5mm: wire‘nf‘lenglh I. h»: Fifi-med into the fihflpfl'. Eth- shnwn in the figure. Cainulnte: the magnenc fiefd El pnim F’. the center mum nilfcuinr 5egmfint. 1 In tETI'HS flf'cfln5tants:.l and L}. Gin: il in uni! x—aflnrnnlfllion. Bfigur ) 11.5. :1. cutlduulillg mii An in the Figure makes contact with the meml mils I'm-and {IB.'l11£-fipparatus 1'5 in a unifm'm mngnetic; fiald B T [Li 'I'. parrpendiculur m the plane fifth: . diagram. :31 Find the magnitude' nftha trnf and dii‘culicm ufthc current J induced in 1h: rod whfin it ismming mwuni right with flCflI‘IETiII'fl speed uh- = 41: WE. Show ahe {Iirectjnn ml. II“: rigurc. afar _ -‘ “ EEHEEL ‘54- SEAL =EA = _T‘.j_m_ E=HE1~J E: whims fill-I: =‘HD'V Eni.nv _ humkmgkfib‘a 1-1-11. b} H" IIIE- resistance uffl'l-e circuit ABCD n: R — 13.2 ohm fussumcd man-smut}. find H11: rum-e, rqqmrad tn move The. rnd with ccnnstam speed. Meghan frict'mn. ---1 —m- E. in I E a. El- F: 23"":H a 53".: '15- 5:“ fib—fii.fi F = a. Lh-Ejfifl-E) = {.15 N IF? I” can-r; c: Find file rain: at which mechanicai wm'k 1-9:. time,ij the appflud Fun-{L P: Fv P=1L115flullfl :5 I-Dw 13:15.13“? Iii} Find Il'lu ml: 91‘ héul dissipatiun in the firm“. 1?:I: .= L‘R P3. =. {5&3me 5: 5.5 w 13325.53.” ...
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112-20012-MT2 - QJ. A par-11'le {mung-1 I11 and clmrgeq is:...

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