112-20042-MT1 - 0 [email protected]{1.1 Three charges are placed as shown...

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Unformatted text preview: 0 6') @i {1.1. Three charges are placed as shown in Ihe figure. The magnitude 0qu is. 15.40 mi, but Sign of charge q. and sign and vein: of the charge q; are not known. Charge q; is +4.11!) “C. and the net Farce F on q; is entirely in the negative x-direeliun. at 5-hour. q‘l. —" :1} Considering the dilTeq-ent pessible signs :3qu and 11;, there are four possible force diagrams representing the flames F. and F; that q. and q; exert on +43. Skew]: these tbur possible force ennfigu ration-5 on the figure: below. ,7 6 7 & F1 Ft "7 ,._ F' r in] 1.3ng the sketches From part It” and the direction [if F. determine :11: sign af'mc e argeg q, and q: (1.49 fie?‘ c: Calculate the magnimde ofehaage cu. wilymLL %%¢W¢ELGV&z Iii-1L tyre. ;' ‘arg-EL .15: m; We. CM) 2') C 1‘. - - i w i the. M- .1 we {a} iii-fl - dfi‘ét. J??? :fin; 3 LEE;— : we. 5 "H iii-1i mitt: Elam“ 33' FM: 7"Wm” ifizi29-3 fr; Gr} {Eh {Elie-15+[fii d-g : J. [on its 1-, 5.6-, $1M?) :- QJ. Point charges (9': - 4-D x1 Ell"cl C and Q; = H.0xlfl" C are separated by 3.0 mm. forming an electric dipole. 6-9 3} Find the magnitude nfd‘ne electric dipole mmnent. ii= ‘ii ={txrt'3clé3xm‘ f... ."‘. '1“; hi Thit‘r diwit iii in il UHiTGI'I'I'I nil-Will: iiEId when: direction makes an angle el‘ji" with the line 2L:- ' connecting the charges. 1Iii-"Ital is the magnitude oi‘thr electric field il‘the torque exerted an the dipole ltaedmagnitude 7-.1 a:- | lil'a N.rn'.“ t=P55m3 a» £=._ai __ FEM-5" Jl'n '3 F'__*.L}it'fl‘t'-iu'lt '.'.' E=lr13tdfc ' 5:11: L2] What Wfiri'i is rtquired to change the erienlatien of the dipole in the eleeuic tit-Id gladly From 3?’ "r" to W“? 111,3. .J. nan-umtdueting sphere af‘radius R has a mental charge 2Q,wi.th spherically Symmetric distribution of Valium: charge density p = A r, when: A is 1 ennslam. it is. concentric with a unnductingsphea'ical she-Ii uni—inner radius 2R. fluter radius JR and tutu] eharge Q as shown in the figure. |: 05] :1] Calculate the canmmt A in mm: cr‘ GI and R. ,1 r [2. 1. i _+ 2.01 = l; feii'J = “a {Ina} Lh’iiriueir‘] :- {139' r_'__ I = ”-4 :1 G a Ir'l a -; 1M.“ : Pi: -"——. A - 11 -" 1} Iii" #:2'Qffl.{'r in“ b] 33.- using Gauss's Lat-tr. calculate the electric field . in terms 01'5“ .0 and R. within the man- eundueting aphere as :1 Function et‘r'where r“6 R. .1 G . r .- 5*- .3-_.*.q..t-.‘-’r v' E, --1 .-.' Jr b * “Mr"| the nfir' " "fla- t - .u- 1;-._F__é‘:_' -_-..__..——.. '='-' "' . " .- ; - x. 1;. -.._. 5.: raw-- 1‘ 4H1 '3=-'—":. .’ Ina J.‘, {9115' e: Find the charges on the inner surface and outer surface c-t'the conducting spherical shell. lfifizi- fiat-"$13.1 . --?.G I A ’1' .. 5._.~ “IL-.73“, [D 5} d} B} using Gauss's Law. calculate the electric field. in lite conducting spherical shell as :1 Function of : uhetc 2R< r 4 3R. \ E -,-_ O i .wymigm 1. Li"-.‘t-~..L.I‘":r m n U QA. Tim thin rings with equal radii Inf F'I have total :icctrII: charges +0 and -20 dislribuled unifamly. The}: an: placed parallel to each other along their common axis as Shawn in the figure. The distance hem-can their centers A and E is (JIMR. a} Find the potential at the ecmcrot'the first ring. paint .I'II I'in terms of END and R]. HM... r" f-t'EE. {luff—p.“ L- xt III Warm ‘ " "Lg EITHER. IIIII : i emit. e - i RV = __ 29 - “ft = ‘4 sat-3'? '.2IIIII: E @213 b] Findthep-alenlialalthecenmrat‘lh: secondring, pointBtintemsmEo. (Jami R}. \IQ = A _i__ MS 1 LMJL IE + L; F1") “Ida: 3e Jewel 84-1.3: “fl- HIE-EJL \I'g __ UR 4.1”- “i =flL 2mm. —1L I 24: 1 .rI FiIIIi [I'IL' errL inquired 10 name a charge «:1 Frnm paint B to poi!“ .11.. w “in = LEA—mg F'F'l '~. : ‘31 {\‘dfi— U2 ,1} L—i— + .11 24mm. new} mw=.é@t w flatware '" J . “Jan. —-- {1.5. A spherical capacitor is Famed fiom two mnmntrifi.‘ Spherical. conducting sheiis separated by air. The inner sphere has radius a = 4.5 cm and the cuter sphere has radius [1 = 9.1} cm. A potential difference of?! = 3|} V is applied to the capacitor as shown in. the figure. ® 3.} Find the capacitance pfthe capacitor. @ in Find the charge on the inner sphcrc. 9 = C “at. _..|.1 = {Les-c Mtge-pi —|_o -—_-_‘E..::I.-|.-CJ C- Q Ii Li ; i-‘J Find 1hr: magnitude ef the electric field. at r = M cm. them :he center pf'lhe inner sphere. I ..-— . reg E: 6' JI ‘55 \éfli‘a 4: anti}? “KER-'1 (when)z '5 E = 1.0 {.13 guy if. 3- . 2.3 1 H} 'N/ @ :1} Find the energy stored in the capacitor. L Chi Li: 3.1..5‘j ...
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