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Unformatted text preview: MIDDLE EAST TECHNICAL UNIVERSlTY TIME: 1mm EM!!!
(D DEPARTMENT OF PHYSICS
PHYS 1G5 SECOND MIDTEHM EXHM mg MINUTES L“ etaamine Fill in this I: with. unet with neil LAST NAME FIRST NAME mm! SIGNATURE SECT. GRADES:
m There are 4 classical type problems. 'feu must selve all ef them. Caieuiater net permitted. De net ash: meters any questien about the problems; read. understand and Solve. The steps the solution ef eseh preblem must he shewn eleerlz.r in the space provided.
Humeﬁes] answers must be given with mneet SI units and SI unit symbols must he used enly. 5
g=eme= 3 1
I h... PEBBLEM {I} [15 points} A 13.5ng hleek eﬂaehed to a spring of relaxed length 3.6 rn and force constant k = It[l Mint. is l: = serum
at rest at point A on a frictionless herizentnl
Surface. A constant hem'zenta] feree F = 212) N is "re—n71
then applied to the bleek and I'IID‘III'ES the bleelt A B to the right aleng the surface. H..— m; m __.+..;_ [1.25 [11...]
{a} What is the speed of the hleelt when it reaches paint 3 whieh is (125 In to the right {if point A? use;
F=2I2IN n @ LVFJE'}; ﬁjfrr‘ﬁ): :Eﬁfif’ﬁ
l
{£e){es.£5) {if {ea{ea} : Zita?“ if“: FE: ﬂit/J" F'th It}: Second Midterm Page J' Dec. I3; 1995' Eh]: When the block reaches point B. the force F is suddenly removed. In the subsequent motiont
how close will the block get to the well? 4 5' PRDELEM {2} {15 points] A small block of mass m = 0.1 kg is released from rest at point A at a height h : ] m abete the
ground. It slides down the track as shown in the ﬁgure. it tesehes point B with speed 1:3 = 4 mt's.
From point B it slides on a level surface a distance d = I m to point C which is at the bottom of a
vertical circular loop of radius R = {1.13 m. This circular section of the track {C 4 D —.l E) is
frictionless but the remaining section {A —i 3 —Ir C]: is rough. {a} How much work is done by friction as the bloelt slides down from A to It? 62 Wt. W1._
3 5 kiwi/tits) g‘e. 2 it re} rg} : +5é‘3 Phys 1'05 Second Midterm Page 3 Dee. 1'3. {999 (bl What is the minimum speed with whieh the black must reach point C. if it is not to fall off at the
top {point E} of the circular Imp? I .r' ,
EMILE : EMF. 1.3:“:ng
1L 522:9 Eff E I; %:Mj
it firNV: = ire R
.35 “c ,2 (5) = ﬁéﬁmﬁm; = 3m ; {e} The coefﬁcient ef kinetic fﬁetiett between the hleelt and level surface {between E and C} is“.
What sherulel he the vaEue of M SCI that the three on rhe Heck by the track at point D is equal tel its weight?
1; 55 a we fed/3m)
eeelmﬁ P :5“? = W319 A
~1ﬂ$ ,4? ff :9 m erger}? J 3.3,: ; “E;
iii“fie '§”‘%L=~x‘e’iy J PM: we seem Midterm Page 3 Dee. 13, I999 PROBLEM (s) {25 points} While mering heriztmtally at speed v 2 5t] mJ's at an altitude h = 125 "L a shun “Panda; and
breathes inte twe fragments of equal mass which fall freely. ﬁne of the fragments has :ere speed tight after the explﬂsion and lands an the ground directly:r below the point 101' explosion. Ignore air
resistance. {h} [n unit vectttr t:+:ntatit:+111 ﬁnd the velocity ef the eenter of mass of the [wefragment system 3 s
after the explusiun. Em 5: I?” [If‘5') + Rem f wﬁfre aim: vjﬁ'}
—r A in
wﬁiff=§i2= {ﬁt *jﬂﬂ—f‘ ,rn m/J’ Phys H1!" Second Midterm Page 4' Egg, :3, £999 {c} Find the x and _t'cuurdjnntes of the cenler Elf mass of the twofragment system 3 s after the
EIplﬂSiDn. —3 —4 —I. _; l [3“) ,gmt’e; = amen yam2M +3 3:,“ 15
it? (Mr): Mi? + ’55 3"; :1 (40):? if
an g?“ PROBLEM (4} [25 paints} A mass ml sliding with a speed of 5 m.I'5 an a hen‘zentel ﬂmr mLIJdes with anether mass mg sliding
with a speed of 3 We on the same ﬁrm! as Shawn in Fig. I. The speed of H11 after collision is. again 5
We and it is meving in the direction shown in Fig. II. Take m. = l kg and m2 = 4 kg. FigJ Fig. II it: {:1}What is the direction of motion at“ mass #1: after the enlﬁsiun, Le, a ='? @ 5r: *5'5w1'3?°+ fkgfsm'ﬁ
I2 = Feat 3?d+ évgfﬂﬁ Phys i'ﬂ'j Strand Midterm Page 5 Der. I3. I??? {b} Haw much kinetic energy is last in [he tullisiﬂlﬂ' 1
_. f
# fmzt'bér'ﬂ 315/; GD 3 g: 1‘an 55423‘ = 5 Lgﬂ _I.. .4 In. 7:) L§M=4ﬁ1§g n—i m/r [cl]. In unitvector1otation.caculale the jmpuJSI: dtlivcred to each mass during the cuiiisinn. "‘4 "'4'" .4 All}? : ﬁl‘gf
=—5"Hn3? {ea—M3?
: ~3:*4;Ff¢ : #8" 21 _1 .3 A _
Afzi—ﬁf} : yfl'fé‘; ,m I'LL; Phys J05 Swami .ﬁfa'a‘Ismr Page 6 ﬂat. IE. NW ...
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