105-19991-MT2 (1) - MIDDLE EAST TECHNICAL UNIVERSlTY TIME:...

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Unformatted text preview: MIDDLE EAST TECHNICAL UNIVERSlTY TIME: 1mm EM!!! (D DEPARTMENT OF PHYSICS PHYS 1G5 SECOND MIDTEHM EXHM mg MINUTES L“ eta-amine Fill in this I: with. u-net with neil LAST NAME FIRST NAME mm! SIGNATURE SECT. GRADES: m There are 4 classical type problems. 'feu must selve all ef them. Caieuiater net permitted. De net ash: meters any questien about the problems; read. understand and Solve. The steps the solution ef eseh preblem must he shewn eleerlz.r in the space provided. Hume-fies] answers must be given with mneet SI units and SI unit symbols must he used enly. 5 g=|eme= 3 1 I h... PEBBLE-M {I} [15 points} A 13.5-ng hleek eflaehed to a spring of relaxed length 3.6 rn and force constant k = It-[l Mint. is l: = serum at rest at point A on a frictionless herizentnl Surface. A constant hem'zenta] feree F = 212) N is "re—n71 then applied to the bleek and I'IID‘III'ES the bleelt A B to the right aleng the surface. H..— m; m __.+..;_ [1.25 [11...] {a} What is the speed of the hleelt when it reaches paint 3 whieh is (125 In to the right {if point A? use; F=2I2|IN n @ LVFJE'}; fijfrr‘fi): :Efifif’fi l {£e){es.£5) {if {ea-{ea} : Zita?“ if“: FE: flit/J" F'th It}: Second Midterm Page J' Dec. I3; 1995' Eh]: When the block reaches point B. the force F is suddenly removed. In the subsequent motiont how close will the block get to the well? 4 5' PRDELEM {2} {15 points] A small block of mass m = 0.1 kg is released from rest at point A at a height h : ] m abet-e the ground. It slides down the track as shown in the figure. it tesehes point B with speed 1:3 = 4 mt's. From point B it slides on a level surface a distance d = I m to point C which is at the bottom of a vertical circular loop of radius R = {1.13 m. This circular section of the track {C 4 D —.l E) is frictionless but the remaining section {A -—i 3 —Ir C]: is rough. {a} How much work is done by friction as the bloelt slides down from A to It? 62 Wt. W1._ 3 5 kiwi/tits) -g‘e. 2 it re} rg} : +5-é‘3 Phys 1'05 Second Midterm Page 3 Dee. 1'3. {999 (bl What is the minimum speed with whieh the black must reach point C. if it is not to fall off at the top {point E} of the circular Imp? I .r' , EMILE : EMF. 1.3:“:ng 1L 522:9 Eff E I; %:Mj it fir-NV: = ire R .35 “c ,2 (5) = fiéfimfim; = 3m ; {e} The coefficient ef kinetic ffietiett between the hleelt and level surface {between E and C} is“. What sherulel he the vaEue of M SCI that the three on rhe Heck by the track at point D is equal tel its weight? 1;- 55 a we fed/3m) eeelmfi P :5“? = W319 A ~1fl$ ,4? ff- :9 m- erger}? J 3.3,: ;- “E; iii-“fie '§”‘%L=~x‘e’iy J PM: we seem Midterm Page 3 Dee. 1-3, I999 PROBLEM (s) {25 points} While mering heriztmtally at speed v 2 5t] mJ's at an altitude h = 125 "L a shun “Panda; and breathes inte- twe fragments of equal mass which fall freely. fine of the fragments has :ere speed tight after the explflsion and lands an the ground directly:r below the point 101' explosion. Ignore air resistance. {h} [n unit vectttr t:+:ntatit:+111 find the velocity ef the eenter of mass of the [we-fragment system 3 s after the explusiun. Em 5: I?” [If-‘5') + Rem f wfifre aim: vjfi'} —r A in wfiiff=§i2= {fit *jflfl—f‘ ,rn m/J’ Phys H1!" Second Midterm Page 4' Egg, :3, £999 {c} Find the x- and _t'-cuurdjnntes of the cenler Elf mass of the two-fragment system 3 s after the EIplflSiDn. —-3- —-4- —-I. _; l [3“) ,gmt’e; = amen yam-2M +3 3:,“ 15 it? (Mr): Mi? + ’55 3"; :1 (40):? if an g?“ PROBLEM (4} [25 paints} A mass ml sliding with a speed of 5 m.I'5 an a hen‘zentel flmr mLIJde-s with anether mass mg sliding with a speed of 3 We on the same firm! as Shawn in Fig. I. The speed of H11 after collision is. again 5 We and it is meving in the direction shown in Fig. II. Take m. = l kg and m2 = 4 kg. FigJ Fig. II it: {:1}What is the direction of motion at“ mass #1: after the enlfisiun, Le, a ='? @ 5r: *5'5w1'3?°+ fkgfsm'fi I2 = Feat 3?d+ évgfflfi Phys i'fl'j Strand Midterm Page 5 Der. I3. I??? {b} Haw much kinetic energy is last in [he tullisifllfl' 1 _. f #- fmzt'bér'fl 315/; GD 3 g: 1‘an 55423‘ = 5 Lgfl _I.. .4 In. 7:) L§M=4fi1§g n—i m/r [cl]. In unitvector|1otation.ca|culale the jmpuJSI: dtlivcred to each mass during the cuiiisinn. "‘4 "'4'" .4 All}? :- fil‘gf =-—5"Hn3? {ea—M3? : ~3:*4;-Ff¢ : #8" 21 _1 .3 A _ Afzi—fif} : yfl'f-é‘; ,m I'LL; Phys J05 Swami .fifa'a‘I-smr Page 6 flat. IE. NW ...
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This note was uploaded on 07/28/2011 for the course PHYS 105 at Middle East Technical University.

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105-19991-MT2 (1) - MIDDLE EAST TECHNICAL UNIVERSlTY TIME:...

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