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Assignment04_OROUR - 4.15 a) samplepoint x=3 x=2 x=1 x=0...

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4.15 a) Identify the sample points associated with this experiment and assign a value of x to each  sample point. x = 3 x = 2 x = 1 x = 0 HHH HHT TTH TTT   HTH THT     THH HTT   b) Calculate p(x) for each value of x: x = 3 1/8 x = 2  1/8 + 1/8 + 1/8 = 3/8 x = 1 1/8 + 1/8 + 1/8 = 3/8 x = 0 1/8 c) Construct a probability histogram for p(x): d) What is: P(x) = 2 P(2) = 1/8 + 1/8 + 1/8 = 3/8 = 0.375 P(x) = 3 P(3) = 1/8 + 1/8 + 1/8 = 3/8 = 0.375
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P(x = 2 or x = 3) = P(2) + P(3) = 3/8 + 3/8 = 6/8 = 0.75 4.36 a) Find E(x): E(x) =   x*p(x) 0(.09)+1(.30)+2*(.37)+3*(.20)+4*(.04) = 0+.30+.74+.60+.16 = 1.8 E(x) = 1.8 This means between one and two homes will have the probability of having high dust mite  levels. That is equivalent of 67% of homes listed in the question. It is likely that one entering any  given home will have a high probability that the home will have a high concentration of dust  mites. As dust mites are a common allergen affecting a large number of people, most people  with allergies will be suffering at home.
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