# OR3 - OBJECTIVE FUNCTION VALUE 1 280.0000 VARIABLE VALUE...

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Consider Dakota example discussed in modeling. Use the Lindo output in the figure given to answer the following questions. a. If the price of a table is \$ 40, what would be the new optimal solution to the problem? Current basis is no longer optimal b. If the price of a table is \$ 25, what would be the new optimal solution to the problem? Still \$ 280 c. If the price of a desk is \$70, what would be the new optimal solution to the problem? \$ 300 d. If maximum available finishing hours were 25 hrs., what would be the profit? Current basis is no longer optimal e. If maximum available finishing hours were 18 hrs., what would be the new profit? \$ 260 f. If maximum available lumber were 38 board ft., what would be the new, profit? Still \$ 280 LP OPTIMUM FOUND AT STEP 2
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Unformatted text preview: OBJECTIVE FUNCTION VALUE 1) 280.0000 VARIABLE VALUE REDUCED COST X1 2.000000 0.000000 X2 0.000000 5.000000 X3 8.000000 0.000000 ROW SLACK OR SURPLUS DUAL PRICES lumber) 24.000000 0.000000 finishinq) 0.000000 10.000000 carpentry) 0.000000 10.000000 demand) 5.000000 0.000000 RANGES IN WHICH THE BASIS IS UNCHANGED: OBJ COEFFICIENT RANGES VARIABLE CURRENT ALLOWABLE ALLLOWABLE CQEF INCREASE DECREASE X1 60.000000 20.000000 4.000000 X2 30.000000 5.000000 INFINITY X3 20.000000 2.500000 5.000000 RIGHTHAND SIDE RANGES ROW CURRENT ALLOWABLE ALLLOWABLE RHS INCREASE DECREASE lumber 48.000000 INFINITY 24.000000 finishinq 20.000000 4.000000 4.000000 carpentry 8.000000 2.000000 1.333333 demand' 5.000000 INFINITY 5.000000...
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