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Unformatted text preview: ChE 210: Meeting 6 January 24, 2011 Outline (F&R Sections 4.24.3) Homework Due Friday 01/28/2011
 Balance Equation 3.15, 3.16, 3.19, 3.32, 3.40, 3.41,
 Labeling Process Flow 3.48, 4.4, 4.7ac, 4.23
Diagrams
 Scaling Process Flow
Diagrams  Basis of Calculation Example 4.22
(Problem—Solving Process) One thousand kilograms per hour of a mixture of benzene (B) and toluene
(T) containing 50% benzene by mass is separated by distillation into two
fractions. The mass flow rate of benzene in the top stream is 450 kg B/h
and that of toluene in the bottom stream is 475 kg T/h. The operation is at
steady—state. Write balances on benzene and toluene to calculate the unknown component flow rates in the output streams.
1. Read the entire problem statement. 2. Draw a process flow diagram. 3. Label the diagram with all of the known information. 1/10 ChE 210: Meeting 6 January 24, 2011 WWW = 450 kg/h m T,outT = Out, Top min =1ooo kg/h In
XB’in = 0.5
XT,in = 0.5
. Out, Bottom
mB,outB =
m T’OutB = 475 kg/h 1 ' ‘Ewk‘~ '1“.
w r, *deng gem be labeled mm Mod 43mm ((1,463) or
_ Compunen¥ Rum rc 9i;
4. List all other given Information 5. Identify values to find " H‘mﬁ; A 2/10 ChE 210: Meeting 6 January 24, 2011 6. Write and simplify the general balance equation for total mass and each species In + Generation — Out — Consumption = Accumulation ‘/ J Total Mass: m , 3 W ~ {my .,. "F‘r‘  v A
i \v..  l \w ’  "
\.\'v[ i :_ VJ? kiwi!) W w ‘
Benzene: ‘ ‘/ ,
[xi/Six “‘ 1'?“ 1"“
. sun 51%;. t "I‘ 1%,. r Tl e: «t ,t Cue“ mg ~ MT ',:Q \AJX l ‘“°5v’<v,.g.f’ 7. Develop a solution strategy  idgnHR‘ knouns in 8. Solve and check solution l’d. — "t \t .L ‘
KC, Fig: i ‘93:; ktjlly * n" ‘ "r1 (putt); ‘ \
(1 lY‘i 3' r; 7“ r l l *1 Ltd 1’s; k ,.)Mw"“+5.!“‘3 “import LN") ’4')?“ \ I 3/10 erbuaﬁms IST ChE 210: Meeting 6 January 24, 2011 Labeling Process Flow Diagrams
Typical variable labels for each stream: 1. Total mass flow rate and species mass fractions 2. Mass flow rate of each species 3. Total molar flow rate and species mole fractions 4. Molar flow rate of each species Need all streams to have consistent units. Can combine 1 and 2 or 3 and 4 on a single process flow diagram, but cannot mix mass and molar variables. 4/10 ChE 210: Meeting 6 January 24, 2011 Handout A liquid mixture of benzene and toluene contains 58.0 mole % benzene.
This mixture is to be partially evaporated to produce a vapor containing
85.0% benzene by mass and a residual liquid stream containing 10.6%
benzene by mass. This process will be carried out continuously, at steady
state, with a feed rate of 1200 moles/h. What are the mass flow rates of the liquid (mL) and vapor (rhv) streams exiting the evaporator in units of kg/h? (Note: You will need to use information from Table 8.1 in Felder and
Rousseau) a) Draw and label the process flow diagram. Use consistent units for all
of the streams. 5/10 ChE 210: Meeting 6 January 24, 2011 **Need to convert feed stream to mass flow rate and mass fraction** "'1 \o KO v v v ' i
‘:;4L%fgwambww*mam
mm gooCe) " Q : 93341316 : . Q . 581;; y '1 RCC‘W‘M
in Tolkmﬁ 1 0‘4 \ c 2 xx \ . ﬁb\_\3&>bmo\\ 13~\~1j N m : «LN/1‘14 {Lng h "9 (Y‘s T “W
h (MM “9003 J ' H 5“ 553st; J? \‘BTC * ‘ . {ii—u Li R, a. i h
Nam : 7~~ ‘
\ ‘ v .. O. "' a
ELM» ‘—\ H: (5/ ‘ “r HEM FL?“ \ Hq quc’
J a _ Hug kgj/h 5m 1561;.“ MW Wm '~’ O" "4‘90 ‘anwmm+@ﬁﬂ:aﬂwﬁnw%Hg7mwswgh 6/10 ...
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This note was uploaded on 07/31/2011 for the course CHEM E 210 taught by Professor Shanks during the Spring '02 term at Iowa State.
 Spring '02
 Shanks

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