Lecture29 - ChE 210: Meeting 29 March 30, 2011 Outline...

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Unformatted text preview: ChE 210: Meeting 29 March 30, 2011 Outline (F&R Sections 8.0-8.4) Homework Due Friday 04/01/2011 - Hypothetical Process Paths 7.19, 7.29, 7.42, 7.51 a&b - Review AH with AP - Review Sensible Heat and Heat Capacity - Latent Heat Example Problem 100 mol/h of a liquid mixture of 25 mol% toluene (T) in acetone (A) at atmospheric temperature and pressure (T = 25 C and Pabs = 1 atm) is fed to an evaporator that operates at 120 C and 1 atm. All of the liquid is vaporized. Heat is provided to the evaporator by condensing saturated steam at 10 bar. Calculate the amount of heat that must be supplied to the evaporator and the mass flow rate of saturated steam. nin = 100 mol/h nout = xAJn = 0.75 mol A/mol xA’OUt = xTiin = 0.25 mol A/mol xT’out = Out Saturated Steam Water (L) Pabs= 10 bar P: 10 bar Given: Reference T, P and A A phase Hin (kJImol) Hout (kJ/mol) Acetone 25 C, 1 atm, liquid 0 39.7 Toluene 25 C, 1 atm, liquid 0 49.5 1/5 ChE 210: Meeting 29 March 30, 2011 1‘ Hypothetical Process Paths ’ic (Lamas 13H reminxzetu (figfli’Et/tt Three main components of hypothetical process paths: 1. AP at constant T and (1) (Section 8.2) \ Ideal Gas: [fix H #540 Liquid/Solid: A H \Q’AP Nonideal Gas: 7 Heed, +1"¥:i:'ani“~pf;ia,,imime Kitlhu’xizi‘xlpfi 2. AT at constant P and 4) (Section 8.3) ’2. \ 35$}! : \ C0 d7 [’L‘afiflixbw Wava :_ i ‘i a . v» V- ‘ . _ ‘r’f (0,. V) 551516 «tyx‘v‘LfiL-Wh. :0 MUN ‘3‘ «~ ‘2‘ Check $0.in kiscnd/ W346 /‘W5’C~"3 *C'hzci: 1m 4:5{13 afguwxm 3. mp at constant P and T (Section 8.4) l\ I\ ‘ h K r/ ‘ ’ UCQVUQ‘L [rm—J) \{Q‘PW [‘3 H '- A’H'v (‘Ttr ) (/i Lakifiq'xt he}; 7i % I) i" ",1 /\ I»\ k_\ I 7 Yr) . ) fl \ xx 1 L T, r 1 (jg/4" L\Q_»LL;A!_>SCA\d AH : BHn'fi 4m i J G ‘ ’ flcr (WU. Tl) t2,ch Tn”, A}, j W had a mam-,3;an (La v‘) 3 “am /\ A Hm 5 hem cg 1w; cm (L a? 1;) ‘* (EVBI’SQ (gum is" amt/1:; Wu} V4 L 0’ 1'3 ->L U 1 2/5 ChE 210: Meeting 29 March 30, 2011 Example Problem Revisited nin = 100 mol/h nout = XAJn = 0.75 mol A/mol xAyou,t = xTyin = 0.25 mol A/mol XT,out Out Saturated Steam Water (L) Pabs= 10 bar P: 10 bar “PM 9‘ L “V :: a w Fa “L: *Ti’fifif 51L: A A :7 .17 A A 2&13’11’13; UL. lit. he. E; 3 Reference T, P and phase Hin (lemol) Hout (lemol) Acetone \ {if} 1; ltj i‘l‘_ .1" ‘ -x l d! {k . a a“. H 3 ‘ .bulflA/“mr/ I \ ‘ l ,v r '.- ). a; - '- x41: (Adm \ Toluene w j-U‘l 1;“ tv‘fir‘l’v’w ‘ ‘15 Meme. {\th (“Val 4.71. Hf MK”, g'L-(‘l‘l 75 (£4531;le Energy Balance (SteamNVater): , , l l » , l w y l :7 X“ l 1 . “I r ' a ' ,. 5 ' - ; > ; x ‘ eflajdlxw ’ ,a _\ in“ ’ t1] I I“ K ,1 u I _, ._ g“ " “gill ( I L ,: ‘03 Energy Balance (Acetone/Toluene): 1"“, _ a. I _ g \_\ (Luv? \5 ll‘x‘ L~\ , , I _ I 1 A A ~r, \ "/7. ‘ .V‘r K ‘J x" .1 7V ( A ‘ «w.:l"“1‘c*t ‘ "" .; “*5 w ’ ,. H + , kw \ U M h “Hug ! by 4'3.) ‘\\“‘ l‘xy‘lilm a HI l“ ’K‘Tn 1t". "2"} r- ., ' .. g} L' x w k ,. Q x L}; Yf‘f; ChE 210: Meeting 29 March 30, 2011 Hygothetical Process Path (Acetonel Keg Hcvmu' MTG! “14ml W _ , — —-» r ‘ (lid-“C; 1/le V) .4 2 AT 9‘71» \ (Eh-91.} Cam, L. ) AT A¢ muogtmxv) Calculated Enthalgy of Acetone l\ A ,\ .x 45H = AHTQS-flm‘c; ImmL) + AHV ’r AHé‘bm!90“C,Ia/*m\13 > i A 5m 95 1 jC'F’dT AHA— ‘Q1+ bT +QTZ *dTg NT Emmi—£31 515:) 3 -, - . K . ‘ $321139 MD b: \‘G-M’b C=u d=U A ‘zgk: {5&1 LO; HOT ’rCTl-r c1143 d T tumgx I ‘ . ‘ n W - ‘8 ‘ fl » y‘IJ- W a qukgmgs b~.1;0.‘\QMQD a: anywmo d : dHJuML» AMY = 30:42 mum} 4/5 ChE 210: Meeting 29 March 30, 2011 H othetix aI‘Process Path Toluene K6 _ Lift Scum Lulu-cl 3 — I ~» « ' ~ > (/9101; Li rm] V) 1“, AT ,ET‘T) U/O‘UQZUC \LUTm L) QT 2" / Cumin )aij) Calculated Enthalgy of Toluene AH g'AFLL‘AMI'OKC' ‘Q‘ml‘J 'V AHV + AHTC‘)0.@01°C-> iao"c,\cwn.v) \ Z th’dT chk JAGng an A No.91 ANT: C“ + b7 J“ CTziyd’TU CH CH my} 1.) CL: lq8:8.>8)053 b: 352.4700” ““ 1&0 I “ Mn = J in HGT +cT2+ (173:1 dT [flu/mng H0 5) ‘62. O J _8 -. 1 _ r- a :5 _. , \.‘: N a: Qqfi m, 3 b1 Baezmu c 3212:5000 c1 ' 5L" ) AH¢ 4 353,47 CkJMng—l 5/5 ...
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Lecture29 - ChE 210: Meeting 29 March 30, 2011 Outline...

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