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Lecture36

# Lecture36 - ChE 210 Meeting 36 Outline §F&R Chagter...

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Unformatted text preview: ChE 210: Meeting 36 April 18, 2011 Outline §F&R Chagter 9.0-9.5} Homework Due Friday 04/22/2011 - Review — Problem 9.8 9.1, 9.5, 9.12, 9.27 . Material and Energy Balances . Prayers due m 4135 on Reactlng Processes— , . . , cit/xi W” Problem 9.16 “>ka FWM'C 9"” 5"” town“: .amlj‘ Gamma“ ‘70 1/777“? c ‘ Problem 9.8 CZH4 (g) + 2 Cl2 (g) a CZHZCI4 (I) + H2 (9) AH,0 (1) = —385.76 kJ/mol C2H20l4 (I) e CzHCl3 (I) + HCI (g) AH,o (2) = ? AHf°(CzHCl3, I) = -276.2 kJ/mol a. Calculate AHf°(C2H2CI4, I) and AH,° (2): I ‘"\ u k; . L, A‘ 7‘ a \\l . I, : ,v‘ ,1 .‘ .- g g // 1‘ Q . " I; In lI" U I AW “*LHZC‘H I ii) If buy/(4 H2 1‘3) - AH? LQLHHI ‘3) “ '3? 15145?qu , ‘3) I‘ [5 Dbl) : , " ‘ n ». ‘ . “"1 -. '1‘ " W 5H; (LZHLlaiQ) 1 Ai‘kHu'fl) ~ (Ed? (Q1 H204, X) “.978. 52 Mlmg It-Cla. 3i bum)- ('* 3:55 .ng Um) (I 1/6 ChE 210: Meeting 36 April 18, 2011 b. Calculate AHr° for CzH4 (g) + 2 Clz (g) 9 CZHCI3 (I) + H2 (9) + HCI (g): a; C2H4 (g) + 2 012 (g) e CZHZCI4 (I) + H2 (9) AH,0 (1) = —385.76 kJ/mol (31/ C2H20|4 (I) 9 C2HCI3 (l) + HCI (9) AHrO (2) = 7 . _. , ( . ‘ ' f , and 3‘ l—\\\ {ALILLLLQFJ (ms ((1.4 (junta are on game ode- \‘L {X0 SL1, Q” déberd 04“ ~ 1‘ {All SR.QH\UW\&1Y1Q QC‘Qg‘lCt'V‘h CUE" Whip bikﬂna 5-, All? a) + 5.43 (a) .— AH; (do-sweet) a 58:» m mum + - 5:3 Car-s ulmd‘ - (Ego/<1 tunnel ~R__.=__._.K (‘13.- c. Calculate Q for 300 mol CzHC|3lh produced by reaction in part b (assume all reactants and products are at 25 C and 1 atm): Q ‘- *AH ; 81th? Q .- 3Q; {{3‘5/l‘kl ,qQQﬂQ luJ " _.._ ,.: AAAAA , ..___ 5 m " 2/6 ChE 210: Meeting 36 April 18, 2011 Problem 9.16 nsoz = ' nsoa = n02 = . ' n02 = nN2 = . Air ”302 = Product 502 T = 450 C Water (L) Water (L) T = 25 C T = a. Calculate molar flow rates and extent of reaction: :~ . u A“ ‘ . ,, a j _ _ \ " .‘ _ . . Gwen ‘ macs:5 P = ‘03lean CC‘mpLth 0:”) 0»? Com f ﬂgdz - 37‘" 0°7— © » a5 = 0,, m0 Reachm; "‘v‘ +11W —‘7 (—30 E' = knee-t “0» Gen N2 - ”S (\C ' \ ,_‘ __‘_. __. \ : 0-ch kmcv‘ ’3 meme banana (A C ‘1..,\ ;" u v .. A \ t‘ . ( ® :30]; ' (‘30; - ﬂﬁoz‘p v \$ SL3 a 0302\(3 "- UsOl‘ hnCHXl-A I'MXI ‘ ‘5 - U M L (Ly 0) ' “cam" - nah? ~- “/9153 ;C m9 001.9 10,036 kmM/s ‘ ,3 ‘ ~ ,‘ NL ‘ ”-12.0“ .. “(12,19 : U \ : Framers; Souogcczho T: “M :-\‘ ‘ o x, ‘ c. ‘i‘ Q39 ROLE.) ’ C3495 >- 050: ' 0.42.? e a “so; —= 0.0333 land/S L I? \ (,- V ‘1 Q) A‘exﬂ’bbcu‘r : \oo -= 5902," “SQL‘ 0 mg‘; , .. \mu‘ 9. 37ktC‘Q‘; 9 ' -. ‘- ‘ 0:30.032. 3/6“”? ‘ '12. 4.0, , . \ (‘30; l‘ mu (.3. / tonal/S ”hula-3C:— ChE 210: Meeting 36 April 18, 2011 b. Calculate AHr° and Q using molecular species at 25 C as reference states: ‘ A r J‘ ,4 I~ /C AR" 7 AH? LSCSFS) - AR; (-302 .3) ' A H; "LOZ‘Z'D 5W T 'ﬂSJBMnLeJE + Q‘Kpaqa LI lmw W34 Emma/me: Q (97%: ﬁt; ‘” ‘S/Zﬂ: r AR , "0 L5\A= :0 (3‘4; — 2 (\‘L'Ah‘b + éAH( CLU’ \n 1L _ €64 S’ﬂk (95E mam 3);?” €th :tLLbStCchS ”<er mm a} 444444 cmMms O, L Cmd Nz \ﬂW/rpdc‘d'reﬁl hum T014“? 533.8 ‘ A T e. and 595 "’ ANT) = SCAT W444 qo Rum Table as 25 4/6 ChE 210: Meeting 36 April 18, 2011 0. Calculate the mass flow rate of water if the temperature of the exiting stream must remain below 40 C: Q3 ? H32“ UJS = m” KAH (HDCJ) ’ [5:4 Utiqﬁn va‘sﬁ"lv', .\ 1' . 4 "\r “N U“ M wit;1 -- yoqiicweng) Twig t 1» 5/6 ChE 210: Meeting 36 April 18, 2011 d. Repeat the calculation of Q using elemental species as reference states: ,r" L 555 1’ 1x 9‘ 5t 1355 '1' ‘N V j K )CJ )d.‘ f f y,” c X \, ’ , ‘J T SQ)" J L1 2 lug.) Lr>L3LJ )pT *l‘mra kakLL}(JT ’4“? Crk/Vz)d LL.) 2:) it; 25 E 4:51; L151» 451» ‘ “gr jg (59)er «n f 1 (o ) H “C LN ) (T g, P b C72. {’1 A k MN; J 'r" 2 L 5 L5 ZS 6/6 ...
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Lecture36 - ChE 210 Meeting 36 Outline §F&R Chagter...

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