{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Hand in Assignment 2 Solutions

Hand in Assignment 2 Solutions - CHEM 212(DE HAND-IN...

This preview shows pages 1–3. Sign up to view the full content.

CHEM 212 (DE) HAND-IN ASSIGNMENT #1 (Fall 2008) page 1 of 4 1. (6 marks) Consider a Li 2+ ion with its electron in a 4 s orbital. What is the shortest wavelength of light that can be emitted by this ion? What is the third ionization energy for Li? Give your answer for the ionization energy in kJ mol 1 . (Note: For a hydrogen-like ion, E n = R H Z 2 / n 2 .) Since the energy of a photon is inversely proportional to the wavelength of the light (i.e. E photon = hc / λ ), the shortest wavelength of light is emitted for the transition of highest energy. Starting from n = 4, the highest energy transition is to n = 1. Therefore: E photon = (2.179×10 18 J)(3) 2 [ 1/16 1/1 ] λ = (6.626×10 34 Js)(2.998×10 8 m s 1 ) / E photon To calculate the third ionization energy, use the energy formula above to calculate E 1 . E 1 = (2.179×10 18 J)(3) 2 [ 1/1 2 ] = 1.961×10 17 J IE(3) = N A × |E 1 | = 1.181×10 7 J mol 1 = 11,810 kJ mol 1 2. (12 marks) Sketch plots of R ( r ) versus r , R ( r ) 2 versus r and 4 π r 2 R ( r ) 2 versus r for a 5 s orbital. Repeat the process for a 4 d orbital. Accurate plots are not required (i.e. no calculations are required).

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
CHEM 212 (DE) HAND-IN ASSIGNMENT #1 (Fall 2008) page 2 of 4 3. (6 marks) Use Slater’s rules to calculate the effective nuclear charge for a 4s electron in a ground- state zinc atom. Repeat the process for a 3d electron. The electron configuration of Zn is 1s 2 2s 2 2p 6 3s 2 3p 6 4s 2 3d 10 . The “grouped” electron configuration is (1s) 2 (2s,2p) 8 (3s,3p) 8 (3d) 10 (4s) 2 .
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern