Unformatted text preview: Chapter 28 – Sources of Magnetic Field
 Magnetic Field of a Moving Charge
 Magnetic Field of a Current Element
 Magnetic Field of a Straight CurrentCarrying Conductor
 Force Between Parallel Conductors
 Magnetic Field of a Circular Current Loop
 Ampere’s Law
 Applications of Ampere’s Law
 Magnetic Materials 1. Magnetic Field of a Moving Charge
 A charge creates a magnetic field only
when the charge is moving.
Source point: location of the moving
charge.
Field point: point P where we want to find
the field.
Magnetic field from a point charge moving
with constant speed µ0 q v sin ϕ
B=
4π
r2
µ0 = 4π·107 Wb/A·m = N s2/C2 = N/A2
= T m/A (permeability of vacuum)
c = (1/µ0ε0)1/2 speed of light Magnetic field of a point charge moving with constant velocity ˆ
µ 0 qv × r
B=
4π r 2 ˆ
r = r / r = vector from source to field point Moving Charge: Magnetic Field Lines
 The magnetic field lines are circles centered on
the line of v and lying in planes perpendicular to
that line.
point right thumb in
 Direction of field line: right hand rule for + charge
direction of v. Your fingers curl around the charge in direction of magnetic
field lines. 2. Magnetic Field of a Current Element
 The total magnetic field caused by several moving charges is the vector
sum of the fields caused by the individual charges. dQ = nqAdl (total moving charge in volume element dl A) Moving charges in current element are equivalent to dQ moving with drift
velocity. µ 0 dQ vd sin ϕ µ 0 n q vd Adl sin ϕ µ 0 Idl sin ϕ
dB =
=
=
2
4π
r
4π
r
4π
r2
2 (I = n q vd A) Current Element: Vector Magnetic Field µ0
B=
4π ˆ
Idl × r
∫ r2 Law of Biot and Savart Current Element: Magnetic Field Lines
 Field vectors (dB) and magnetic field lines of a current element (dl) are like
those generated by a + charge dQ moving in direction of vdrift.
 Field lines are circles in planes ┴ to dl and centered on line of dl. 3. Magnetic Field of a Straight CurrentCarrying Conductor µ0
B=
4π ˆ
Idl × r
∫ r2 ˆ
dl × r = dl ⋅1 ⋅ sin ϕ = dl ⋅ sin(π − ϕ ) = µ0 I
B=
4π dl ⋅ x
x2 + y2 a x ⋅ dy
2a
µ0 I
∫a ( x 2 + y 2 )3 / 2 = 4π x x 2 + a 2
− If conductors length 2a >> x µ 0 I ( 2a ) µ 0 I
B=
=
4π ⋅ x ⋅ a 2π ⋅ x µ0 I
B=
2π ⋅ r B direction: into the plane of the figure,
perpendicular to xy plane Field near a long, straight currentcarrying conductor  Electric field lines radiate outward from + line charge distribution. They
begin and end at electric charges.
 Magnetic field lines encircle the current that acts as their source. They
form closed loops and never have end points.
The total magnetic flux through any closed surface is zero
there are no
isolated magnetic charges (or magnetic monopoles)
any magnetic field
line that enters a closed surface must also emerge from that surface. 4. Force Between Parallel Conductors
 Two conductors with current in same
direction. Each conductor lies in B setup
by the other conductor.
B generated by lower conductor at the
position of upper conductor: B= µ0 I
2π ⋅ r F = I'L× B µ0 I
F = I ' LB = I ' L
2π ⋅ r F µ0 I ⋅ I '
=
L
2π ⋅ r Two long parallel currentcarrying
conductors Force on upper conductor is downward.
 Parallel conductors carrying currents in same
direction attract each other. If I has contrary
direction they repel each other. Magnetic Forces and Defining the Ampere
 One Ampere is the unvarying current that, if present in each of the two
parallel conductors of infinite length and one meter apart in empty space,
causes each conductor to experience a force of exactly 2 x 107 N per
meter of length. 5. Magnetic Field of a Circular Current Loop
ˆ
µ 0 Idl × r
µ Idl
B=
B= 0 2
4π ∫ r 2
4π r
µ0 I
dl
dB =
4π (x 2 + a 2 )
dBx = dB cos θ = µ0 I
dl
a
4π (x 2 + a 2 ) (x 2 + a 2 )1/ 2 µ0 I
dl
x
dB y = dB sin θ =
4π (x 2 + a 2 ) (x 2 + a 2 )1/ 2  Rotational symmetry about x axis
no B component perpendicular to x.
For dl on opposite sides of loop, dBx are equal in magnitude and in same
direction, dBy have same magnitude but opposite direction (cancel). Bx = ∫ Bx = µ0 I
µI
µI
adl
a
a
=0
dl = 0
(2πa )
2
2 3/ 2
2
2 3/ 2 ∫
2
2 3/ 2
4π (x + a )
4π (x + a )
4π (x + a ) µ0 Ia 2 ( 2 x2 + a ) 2 3/ 2 (on the axis of a circular loop) Magnetic Field on the Axis of Coil µ 0 NIa 2 Bx = ( 2 2 x +a Bx = µ 0 NI ) 2 3/ 2 (on the axis of N circular loops) (at the center, x=0, of N circular loops) 2a µ = N ⋅ I ⋅ A = N ⋅ I ⋅ (πa 2 )
Bx = µ0 µ
2π ( x 2 + a 2 ) 3 / 2 (on the axis of any
number of circular loops) 6. Ampere’s Law
 Law that allows us to obtain the magnetic
fields caused by highly symmetric current
distributions. ∫ B ⋅ dl = ∫ B dl = µ I
// 0 Ampere’s Law for a Long Straight Conductor µ0 I
B=
2πr µ0 I
∫ B ⋅ dl =B ∫ dl = 2π ⋅ r (2π ⋅ r ) = µ0 I
 Direction of current: right hand rule
curl fingers of right hand around
the integration path , the thumb indicates positive current direction. For an integration path that does not enclose the conductor: µ0 I
B// = B1 =
2π ⋅ r1
− µ0 I
B// = − B2 =
2π ⋅ r2 (circular arc ab)
(circular arc cd )
B and dl antiparallel arc = (angle) x (radius) = θ r
b c d a c d ∫ B ⋅ dl = ∫ B dl =B ∫ dl + (0)∫ dl + (− B )∫ dl +(0)∫ dl =
// 1 2 a b µ0 I
µ0 I
=
(r1θ ) + 0 −
(r2θ ) + 0 = 0
2π ⋅ r1
2π ⋅ r2 B ⋅ dl = B ⋅ dl ⋅ cos ϕ = B ⋅ r ⋅ dθ µ0 I
µ0 I
∫ B ⋅ dl = ∫ 2π ⋅ r (rdθ ) = 2π ∫ dθ =µ0 I
 This result does not depend on the shape of the path or on position of the
wire inside it.
 If the path does not enclose the wire ∫ dθ = 0 around integration path. Ampere’s Law: General Statement
 The total magnetic field at any point in the
path is the vector sum of all fields produced
by the individual conductors. ∫ B ⋅ dl =µ 0 I If the integration path does not enclose a
wire ∫ B ⋅ dl ∫ B ⋅ dl =µ 0 I encl ∫ B ⋅ dl =0 =0 does not mean that B = 0
everywhere along the path, only
that Iencl = 0. ∫ B ⋅ dl 7. Applications of Ampere’s Law
Ex. 28.8 =0 Ex. 28.9 Ex. 28.10 8. Magnetic Materials
 Atoms contain moving electrons, e form microscopy current loops that
produce magnetic fields (randomly oriented, no net Bint). In some materials,
external Bext causes these loops to orient with field, adding to the Bext
magnetized material.
 An electron moving with speed v in a circular orbit
of radius r has an angular momentum L and
oppositely directed orbital magnetic dipole moment
µ. It also has a spin angular momentum and
oppositely directed spin magnetic dipole moment. e
e
ev
I= =
=
T 2π ⋅ r / v 2π ⋅ r
ev
evr
2µ
2
µ = I⋅A=
(π ⋅ r ) =
→ v=
2π ⋅ r
2
e⋅r Model of electron in an
atom Angular momentum of e: L=r×p 2 µ 2 µm
L = r ⋅ p = r ⋅ mv = r ⋅ m
=
e⋅r
e µ= e
L
2m  Atomic angular momentum is quantized: L ~ h/2π (its component along a
direction is always an integer multiple of this value).
(h = Planck constant = 6.626 x 1034 J s)
 Associated with the quantization of L is an uncertainty in direction of L and
of µ (since they are related). e
eh
eh
µB =
L=
= 9.274 ⋅10 − 24 Am 2 or J / T Bohr Magneton =
2m
2m 2π 4π ⋅ m
 Electrons have intrinsic angular momentum (Spin) that is not related to
orbital motion, but can be seen as spinning on an axis. The angular
momentum has an associated magnetic moment with magnitude ≈ µB.
Magnetic Materials
 When magnetic materials are present, the magnetization of the material
causes an additional contribution to B. Paramagnetism
 In an atom, most of the orbital and spin magnetic moments add to zero.
However, in case cases the atom has magnetic moment µB. If such atom
is placed on B, the field will exert a torque: τ = µ×B this torque aligns the magnetic moment with magnetic field
(position of minimum potential energy). In that position, the
current loops add to the externally applied B.  B produced by a current loop is proportional to loop’s magnetic dipole
moment µ
additional B produced by electron current loops proportional
to µtotal per unit volume of material (V) = Magnetization. Magnetization: M= µtotal Units: (A m2)/m3 = A/m V  Additional magnetic field due to M of material is: µ0 M  When a magnetized material surrounds a currentcarrying conductor, the
total B is: B = B0 + µ 0 M B0 = field caused by the current conductor behavior typical of a paramagnetic material.
 The magnetic field at any point in a paramagnetic material is greater by
the factor Km (relative permeability of the material) than it will be if the
material were replaced by vacuum.
 All equations from this chapter can be adapted to the situation in which the
currentcarrying conductor is embedded in a paramagnetic material by
replacing µ0
Km µ0.
Permeability: µ = K m µ0 Careful !
We have used the same symbol “µ” to represent two different
physical quantities, the magnetic dipole moment (a vector), and the
permeability (an scalar). Paramagnetism
Magnetic
Susceptibility: (χm small but >0) χm = Km −1 Km and χm are dimensionless.  The tendency of atomic magnetic
moments to align themselves parallel to
B is opposed by random thermal motion
χm decreases with increasing T. B
M =C
T Curie’s Law
C = constant
T = temperature  An object with magnetic dipoles is attracted to magnet poles. Weak
attraction in paramagnetic materials due to thermal randomization of
magnetic moments. At low T, M increases
stronger attractive forces. Diamagnetism
 Total magnetic moment of all atomic current loops = 0 in absence of B.
 These materials can still show magnetic effects when external Bext alters
e motion in atoms
induced magnetic moment. The additional induced
B has opposite direction to Bext (see Chap. 29).
 An induced current always tends to cancel the field change that caused it.
 Susceptibility χ < 0 and small.
 Relative permeability Km slightly less than 1. Ferromagnetism (FM)
 Strong interactions between atomic magnetic moments cause them to
align parallel to each other in regions (magnetic
domains) even when no Bext is present. Ex: Fe, Co.
 If no Bext
oriented. domain magnetizations are randomly domain M tend to align parallel to field,
 If Bext
domain boundaries shift, domains with M parallel to
B grow.
 Km >> 1
 Ferromagnets are strongly magnetized by Bext and
attracted to magnet.
Saturation magnetization: M reached when all
magnetic moments from FM are aligned // Bext. Once
Msat is reached, increasing Bext will not change M.  For many FM materials, the relation
between M and Bext = B0 is different when
you increase or decrease B0
hysteresis
loop.
 In permanent magnets, after Msat is
reached and B0 is reduced to zero, some
M remains (remnant magnetization).
To reduce M to zero requires B to change direction. Ferromagnetism Ferromagnetism
 Magnetizing and demagnetizing a material that has hysteresis involves
dissipation of energy
materials’ temperature increases. ...
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 Spring '08
 SAHA
 Physics, Charge, Current, Force, Magnetic Field

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