final_key - 1r T hec able f t he I 8 00-kg levator abi n t...

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'| -_-) 1r . The cable of the I 800-kg elevator cab in the figure snaps when the cab is at rest at the first floor, where the cab bottom is a distance d= 3.7 m above a spring ofspring constant k = 0.l5 MN/m. A safety device clamps the cab against guide rails so that a frictional force of 4.4 kN opposes the cab motion.:.) Find the speed of the cab just before it hits the spdr+rg. O,ru,^,i . n W r/Y. - ? ^,*. 11uu*n . 9'*-X1) -l- | L.. , t) to d -- (!rt -0) + l0 - MXdt r\ \z v ' -= 1t 1rt -'t;!r,

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I f,5 - T, = V'n, ru ttl {+nn^3c,l^e- 1 /Lnt_' q0 \,- ^t3. - nt ^ A4ci;y (r) )\t, ) (t) frt-d ()) - ntl _,1 Jq ..{ -= C'iz -1t' LIrr.tr 6.se.) -- l(-6znt Lt4 .s r &,i)t = 16 qn u ( u, + rv,"+ fz, z, i"t t( tr'Jo' tl 'ri N m1 (X+.t) Ittr,l tt )6 {.."t) f 't f.r^ tl' hrg rratJ;A ),r \J cve L-- (m1*nn, t,:d Pt mrQaB 1,1^ ,-| |,rr, ,t\ f =l.r(s- V4-P o'l',t') /^ The three blocks in the figure below are connected by massless cords and pulleys' Data: m1 8 kg, m2 2 kg, m: I kg. The coeffrcient of kinetic friction between mz and the incline is 0.2. (a) Show the free body force diagram. (b) Calculate the acceleration of ml, m2, ml. (c) Calculate tensions on the cords. (d) Calculate the normal force acting on m2.
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This note was uploaded on 07/30/2011 for the course PHY 2049 taught by Professor Saha during the Spring '08 term at University of Central Florida.

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final_key - 1r T hec able f t he I 8 00-kg levator abi n t...

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