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2049_ch25B

# 67 v v3 q3 c3 533 v phy2049 chapter 25 a b 6f 4f 3f

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Unformatted text preview: After switch is thrown to B: V1 = V23 (parallel branches) q2 and q3 in series: q2 = q3 = q23 (C23 = 2μF) Charge conservation: q10 = q1 + q23 48 = C1V1 + C23V1 (V1 = V23) Find V1: V1 = 48 / (C1 + C23) = 8 V Find q1: q1 = C1V1 = 32μC 12V q23 = q2 = q3 = 48 – 32 = 16μC V2 = q2 / C2 = 2.67 V V3 = q3 / C3 = 5.33 V PHY2049: Chapter 25 A B 6μF 4μF 3μF 24 Another Example Each capacitor has capacitance 10μF. Find the total capacitance Do it in stages 2&3 Add 4 Add 5 Add 1 ⇒ ⇒ ⇒ ⇒ 5 μF 15 μF 6 μF 16 μF 2 1 4 3 5 PHY2049: Chapter 25 25 Find Charges on All Capacitors Each capacitor has capacitance 10μF. V = 10 volts q1 = 10 x 10 = 100μC C2345 = 6μF q2345 = q234 = q5 (series) q2345 = q234 = q5 = 10 x 6 = 60μC V5 = q5 / C5 = 6 Find q4, V4 V234 = V4 = 10 – 6 = 4 q4 = C4 x 4 = 40μC 2 1 4 3 5 Find q2, q3, V2, V3 (C23 = 5μF) q2 = q3 = q23 = C23 x 4 = 5 x 4 = 20μC V2 = 20 / C2 = 2 V3 = 20 / C3 = 2 PHY2049: Chapter 25 26...
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