eml 3100 integration no. 1

eml 3100 integration no. 1 - Thermodynamics System...

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1 Thermodynamics System Integrations: gasoline engine driven air compressor Gasoline fuel to engine, $3.50/gallon Gasoline Engine Air Compressor Air, 0.05kg/s, 100kPa 25deg C Air, 650kPa Assumptions for Engine: Ideal Otto Cycle, cold air standard assumptions, r = 8 Assumptions for compressor: Adiabatic, no heat losses or gains Neg. changes in KE and PE for the air Isentropic compression Ideal gas assumption Find hourly cost to operate
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Thermodynamics Strategy Analyze compressor and get power input to provide the flow rate and conditions. Analyze the engine to get its efficiency and with power output of engine = to power input to compressor, get Qin for the engine and then using heating value for gasoline get fuel use rate and then cost per hour to operate. )) ( ) 2 / ) (( ) (( 1 2 1 2 1 2 2 2 z z g V V h h m W Q other - + - + - = - ) ( 1 2 h h m W other - = - Energy equation for compressor: Energy eqn for compressor with assumptions: With the isentropic assumption T 2 /T 1 = (P 2 /P 1 ) (k-1)/k T 1 = 25 + 273 = 298K T 2 /298K = (650/100)^0.286 therefore T 2 = 509K , assuming ideal gas: The power input = mass flow rate * Cp(T 2 – T 1 ) = 0.05kg/s * 1.005kJ/kg K *(509-298)= 10.6 kJ/s or 10.6 kW (14.1 Hp) If you use the ideal gas table for air (table A7.1), and use h at the temps.
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This note was uploaded on 08/03/2011 for the course EML 3100 taught by Professor Sherif during the Summer '08 term at University of Florida.

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eml 3100 integration no. 1 - Thermodynamics System...

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