eml 3100 integration no. 3

# eml 3100 integration no. 3 - Thermodynamics Assume steam...

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Thermodynamics 480 deg F, 250psia Satd liquid water at 70 deg F Assume h = 0 Assume inlet temperature is 40 deg F and that you cannot have more than a 5 deg temperature rise through the condenser. Sp.Gr. Sea water = 1.028 Assume heat delivered to steam is 2 x 10 8 btu/h What is total power delivered by the two turbines in Hp? What flow rate of sea water is required? Assume steam generator heat losses are minimal. What flow rate (gpm) of pressurized water is required to deliver the steam if the water enters at 500 deg F and 1600psia and leaves at 490 and 1600psia? 3 4 1 2

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Thermodynamics Let’s get our enthalpies first: h1 = h2 = 38.09 btu/lb h2 = 38.09btu/lb h3 = 1252 btu/lb , s= 1.583 h4 = 836.9 btu/lb Flow rate of steam = Q in / (h3-h2) = 2 x 10 8 /(1252-38.09) = 164,757 lb/h Combined turbine output = flow rate of steam*(h3-h4)= 164,757*(1252-836.9) = 68,390,573 btu/h or 20MW or 26,726 Hp. Heat rejection from condenser = flow rate of steam *(h4-h1) = 164757*(836.9-
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eml 3100 integration no. 3 - Thermodynamics Assume steam...

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