Thermodynamics
480 deg F, 250psia
Satd liquid water
at 70 deg F
Assume
∆
h = 0
Assume inlet temperature is 40 deg F and that
you cannot have more than a 5 deg temperature
rise through the condenser.
Sp.Gr. Sea water =
1.028
Assume heat delivered to
steam is 2 x 10
8
btu/h
What is total
power delivered
by the two
turbines in Hp?
What flow rate
of sea water is
required?
Assume
steam
generator
heat losses
are minimal.
What flow
rate (gpm) of
pressurized
water is
required to
deliver the
steam if the
water enters
at 500 deg F
and 1600psia
and leaves at
490 and
1600psia?
3
4
1
2
This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThermodynamics
Let’s get our enthalpies first:
h1 =
h2 = 38.09 btu/lb
h2 = 38.09btu/lb
h3 = 1252 btu/lb , s= 1.583
h4 = 836.9 btu/lb
Flow rate of steam = Q
in
/ (h3h2) =
2 x 10
8
/(125238.09) =
164,757 lb/h
Combined turbine output = flow rate of steam*(h3h4)= 164,757*(1252836.9) =
68,390,573 btu/h or 20MW or 26,726 Hp.
Heat rejection from condenser = flow rate of steam *(h4h1) = 164757*(836.9
This is the end of the preview. Sign up
to
access the rest of the document.
 Summer '08
 Sherif
 Fluid Dynamics, Energy, Mass flow rate, Cooling technology

Click to edit the document details