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Unformatted text preview: Lesson 4 Homework Solutions 6.3 Boston Red Sox hitting : a) The probabilities give a legitimate probability distribution because each one is between 0 and 1 and the sum of all of them is 1. b) = 0P(0) + 1P(1) + 2P(2) + 3P(3) + 4P(4) = 0(0.718) + 1(0.174) + 2(0.065) + 3(0.004) + 4(0.039) =0.472 c) The mean represents a long term average number of bases for each time at bat. and therefore does not necessarily have to be a whole number 6.5 Bilingual Canadians?: a) Their corresponding probabilities are not the same; that is, each x value (0, 1, and 2) does not carry the same weight. b) =0(0.02) + 1(0.81) + 2(0.17) = 1.15 6.15 Tail probability in graph : The observation would fall 0.67 standard deviations above the mean, and thus, would have a zscore of 0.67. Looking up this zscore in Table A, we see that this corresponds to a cumulative probability of 0.749. If we subtract this from 1.0, we see that the probability that an observation falls above this point (in the shaded region) is 0.251. 6.18 zscore for given probability in tails : a) First we calculate the cumulative probability for the total probability of 0.02 in the tails. We divide 0.02 by two to determine the probability in each tail, 0.01. Then tails....
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 Spring '11
 Thomas
 Probability

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