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247_James Stewart Calculus 5 Edition Answers

# 247_James Stewart Calculus 5 Edition Answers - or 45 At and...

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=cos (tan sin x ) sec 2 sin x ( ) 1 2 sin x (cos x ) y =2 3 x 2 ± y / =2 3 x 2 (ln 2) d dx 3 x 2 ( ) =2 3 x 2 (ln 2)3 x 2 (ln 3)(2 x ) y =(1+2 x ) 10 ± y / =10(1+2 x ) 9 ² 2=20(1+2 x ) 9 (0,1) y / =20(1+0) 9 =20 y ³ 1=20( x ³ 0) y =20 x +1 y =sin x +sin 2 x ± y / =cos x +2sin x cos x (0,0) y / =1 y ³ 0=1( x ³ 0) y = x y =sin (sin x ) ± y / =cos (sin x ) ² cos x ( ± ,0) y / =cos (sin ± ) ² cos ± =cos (0) ² ( ³ 1)=1( ³ 1)= ³ 1 y ³ 0= ³ 1( x ³ ± ) y = ³ x + ± y = x 2 e ³ x ± y / = x 2 ( ³ e ³ x )+ e ³ x (2 x )=2 xe ³ x ³ x 2 e ³ x 1, 1 e y / =2 e ³ 1 ³ e ³ 1 = 1 e y ³ 1 e = 1 e ( x ³ 1) y = 1 e x y = 2 1+ e ³ x ± y / = (1+ e ³ x )(0) ³ 2( ³ e ³ x ) (1+ e ³ x ) 2 = 2 e ³ x (1+ e ³ x ) 2 (0, 1) y / = 2 e 0 (1+ e 0 ) 2 = 2(1) (1+1) 2 = 2 2 2 = 1 2 y ³ 1= 1 2 ( x ³ 0) y = 1 2 x +1 x >0 | x |= x y = f ( x )= x 2 ³ x 2 ± 42. 43. . At , , and an equation of the tangent line is , or . 44. . At , , and an equation of the tangent line is
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Unformatted text preview: , or . 45. . At , , and an equation of the tangent line is , or . 46. . At , . So an equation of the tangent line is or . 47. (a) . At , . So an equation of the tangent line is or . (b) 48. (a) For , , and 6 Stewart Calculus ET 5e 0534393217;3. Differentiation Rules; 3.5 The Chain Rule...
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