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253_James Stewart Calculus 5 Edition Answers

# 253_James Stewart Calculus 5 Edition Answers - Stewart...

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p ( t )=(1+10 e ± 0.5 t ) ± 1 p ( t )=0.8 80% t ² 7.4 Q = ab t a =100.0124369 b =0.000045145933 e ln b b t = e t ln b Q = ae t ln b =100.012437 e ± 10.005531 t . Q / ( t )= ab t ln b nDeriv( Y 1 , X , .04) Y 1 = ab x Q / (0.04) ² ± 670.63 ± A . ± 670 ± A . P = ab t a =4.502714 ³ 10 ± 20 b =1.029953851 P m 1 = 5308 ± 3929 1800 ± 1790 =137.9 m 2 = 7240 ± 5308 1810 ± 1800 =193.2 P / (1800) ² ( m 1 + m 2 )/2=165.55 / m 1 = 23,192 ± 17,063 1850 ± 1840 =612.9 m 2 = 31,443 ± 23,192 1860 ± 1850 =825.1 P / (1850) ² ( m 1 + m 2 )/2=719 / nDeriv( Y 1 , X , .04) Y 1 = ab x P / (1800) ² 156.85 P / (1850) ² 686.07. P (1870) ² 41,946.56. 3.4 ± ± From the graph of , it seems that (indicating that of the population has heard the rumor) when hours. 71. (a) Using a calculator or CAS, we obtain the model with and . We can change this model to one with base and exponent [ from precalculus mathematics or from Section 7.3]:
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