345_James Stewart Calculus 5 Edition Answers

345_James Stewart Calculus 5 Edition Answers - f ( x )=2 x...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: f ( x )=2 x 1 sin x f (0)= 1<0 f ( /2)= 2>0 f 2 x 1 1 ( ) sin x sin x f x c 0, /2 ( ) f ( c )=0 a b a < b f ( a )= f ( b )=0 f a,b a,b ( ) r a,b ( ) f / ( r )=0 f / ( r )=2 cos r >0 cos r 1 f ( x )= x 3 15 x + c x 2,2 f a b 2,2 a < b f ( a )= f ( b )=0 f a,b a,b ( ) r a,b ( ) f / ( r )=0 f / ( r )=3 r 2 15 r a,b ( ) 2,2 r <2 r 2 <4 3 r 2 15<3 4 15= 3<0 f / ( r )=0 2,2 2,2 f ( x )= x 4 +4 x + c f ( x )=0 a b d a < b < d f ( a )= f ( b )= f ( d )=0 c 1 c 2 a < c 1 < b b < c 2 < d 0= f / c 1 ( ) = f / c 2 ( ) f / ( x )=0 0= f / ( x )=4 x 3 +4=4 x 3 +1 ( ) =4 x +1 ( ) x 2 x +1 ( ) x = 1 f ( x ) P ( x ) a 1 < a 2 < a 3 < a 4 P a 1 ( ) = P a 2 ( ) = P a 3 ( ) = P a 4 ( ) c 1 c 2 c 3 a 1 < c 1 < a 2 a 2 < c 2 < a 3 a 3 < c 3 < a 4 P / c 1 ( ) = P / c 2 ( ) = P / c 3 ( ) =0 P / ( x ) n n n =1 n P ( x ) n +1 P ( x ) n +1 a 1 < a 2 < a 3 < < a n +1 < a n +2 P a 1 ( ) = P a 2 ( ) = = P a n +2 ( ) =0 c 1...
View Full Document

This note was uploaded on 08/02/2011 for the course MATH 1B taught by Professor Reshetiken during the Spring '08 term at University of California, Berkeley.

Ask a homework question - tutors are online