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349_James Stewart Calculus 5 Edition Answers

# 349_James Stewart Calculus 5 Edition Answers - Stewart...

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f 0,6 ( ) 8,9 ( ) f 6,8 ( ) f 2,4 ( ) 7,9 ( ) f 0,2 ( ) 4,7 ( ) 2,3 ( ) 4,4.5 ( ) 7,4 ( ) f 1, ± 3.8 ( ) 5, ± 6.5 ( ) f 0,1 ( ) ± 3.8,5 ( ) ± 6.5,8 ( ) 8,9 ( ) f 0,3 ( ) 8,9 ( ) f 3,5 ( ) 5,8 ( ) 3, ± 1.8 ( ) x x,f( x ) ( ) f / ( x )>0 1,5 ( ) f f / ( x )<0 0,1 ( ) 5,6 ( ) f f / ( x )=0 x =1 f / f x =1 f / ( x )=0 x =5 f / f x =5 f / ( x )>0 f 0,1 ( ) 3,5 ( ) f / ( x )<0 f 1,3 ( ) 5,6 ( ) f / ( x )=0 x =1 x =5 f / f x =1 x =5 f / ( x )=0 x =3 f / f x =3 x =1 f / / ( x ) f x =7 f / / ( x ) f f 1. (a) is increasing on and . (b) is decreasing on . (c) is concave upward on and . (d) is concave downward on and . (e) The points of inflection are , and (where the concavity changes). 2. (a) is increasing on and . (b) is decreasing on , , , and . (c) is concave upward on and . (d) is concave downward on and . (e) The point of inflection is (where the concavity changes). 3. (a) Use the Increasing/Decreasing (I/D) Test. (b) Use the Concavity Test. (c) At any value of where the concavity changes, we have an inflection point at . 4. (a) See the First Derivative Test. (b) See the Second Derivative Test and the note that precedes Example 7. 5. (a) Since on , is increasing on this interval. Since on and , is decreasing on these intervals. (b) Since at and changes from negative to positive there, changes from decreasing to increasing and has a local minimum at
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