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# HW3 - c P A B P A B = P(B Therefore P A B = 0.2 0.1 = 0.1 d...

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540:210:01: ENG PROBABILITY HW 3 2-51. a) P(A) = 0.4 b) P(B) = 0.8 c) P(A') = 0.6 d) P(A B) = 1 e) P(A B) = 0.2 2-54. a) S = {1, 2, 3, 4, 5, 6} b) 1/6 c) 2/6 d) 5/6 2-62. a) P(A) = 86/100 = 0.86 b) P(B) = 79/100 = 0.79 c) P(A') = 14/100 = 0.14 d) P(A B) = 70/100 = 0.70 e) P(A B) = (70+9+16)/100 = 0.95 f) P(A’ B) = (70+9+5)/100 = 0.84 2-66. a) P(A') = 1- P(A) = 0.7 b) P ( A B ) = P(A) + P(B) - P( A B ) = 0.3+0.2 - 0.1 = 0.4

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Unformatted text preview: c) P( A B ) + P( A B ) = P(B). Therefore, P( A B ) = 0.2 - 0.1 = 0.1 d) P(A) = P( A B ) + P( A B ). Therefore, P( A B ) = 0.3 - 0.1 = 0.2 e) P(( A B )') = 1 - P( A B ) = 1 - 0.4 = 0.6 f) P( A B ) = P(A') + P(B) - P( A B ) = 0.7 + 0.2 - 0.1 = 0.8 2-69. a) 70/100 = 0.70 b) (79+86-70)/100 = 0.95 c) No, P( A B ) 0 2-72. a) 170/190 = 17/19 b) 7/190...
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HW3 - c P A B P A B = P(B Therefore P A B = 0.2 0.1 = 0.1 d...

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