Module 3 hw - in physical exercise activities during the...

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Unformatted text preview: in physical exercise activities during the lunch hour? what is the probability that this person is a female who does not engage in physical exercise activities during the lunch hour? A.) To illustrate thing better, for me visual I will understand it better if I used a table so: M = males F = Females E = Exerise 0.12 0.06 0.18 0.45 0.39 0.84 0.57 0.45 1 Now that we have pieces of the puzzle which are represented in yellow & was given to me in the proble fomrulas to complete the rset of the missing vairables that where not given there are the ones in green to verify formulas if needed press "F2" which will show you how I got the missing vairables So the Answer for "A" is .06 B.) Using the graph in "A" the answer is .39 a. If we choose an employee at random from this corporation, a female who engages b. If we choose an employee at random from this corporation, Total 1 E c = not execrise T 2 = Total Relevent Info Lets Say: M = Males F= Females E = Engages in physical exercise activities during the lunc complement ( PG 225 in book) total amount of employess engage in physical activity Moreover, assume that 57% of all employees are male JP (joint probability.) = exercise activities during the lunch hour (PG 241 in bo em I can use E c = T 1 = T 2 = ch hour 18% le ook) woman has a job outside the home? woman has at least one child? selected woman has a full-time job and no more than one child? woman has a part-time job or at least one child, but not both? A.) Total amount regardless of stuatus meaning full or part time as the question didn’t speccify Total Number of Women That Work Full Part Total 307 178 Full= 41% Part= 24% B.) This question states at least "1" which denotes that I have a the minium as 1 but the maxium as 2 so I will consider both variables. Because we a have pool of 750 women and out of that pool of wome 271 of them have at least "1" child and again out of that same pool only 326 women have "2" the rem population has "0" children. Total Number of Women That Have Children 1 2 Total 271 326 1 = 36% a. What is the probability that this randomly selected b. What is the probability that this randomly selected c. What is the probability that this randomly d. What is the probability that this randomly selected 2 = 43% C.) This question is very specific I will represent it below with the following graph: Total Number of Women That Has No more than one Child & has a full time Job 1 Total 98 126 0 = 13% 1 = 17% D.) This question is very specific I will represent it below with the following graph: Total Number of Women That Have a Part time Job...
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Module 3 hw - in physical exercise activities during the...

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