{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

3.11ABBA030409 - 1 3.11 ABBA Recall the reduced AB table...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
1 3.11. ABBA. Recall the reduced AB table from section 3.5. REDUCED AB 1. A . fA B . gA. INF. AL. ALF. FIN. NON. 2. A . fA B . gB. INF. AL. ALF. FIN. NON. 3. A . fA B . gC. INF. AL. ALF. FIN. NON. 4. C . fA B . gA. INF. AL. ALF. FIN. NON. 5. C . fA B . gB. INF. AL. ALF. FIN. NON. 6. C . fA B . gC. INF. AL. ALF. FIN. NON. Recall the reduced BA table from section 3.6. REDUCED BA 1’. B . fB A . gB. INF. AL. ALF. FIN. NON. 2’. B . fB A . gA. INF. AL. ALF. FIN. NON. 3’. B . fB A . gC. INF. AL. ALF. FIN. NON. 4’. C . fB A . gB. INF. AL. ALF. FIN. NON. 5’. C . fB A . gA. INF. AL. ALF. FIN. NON. 6’. C . fB A . gC. INF. AL. ALF. FIN. NON. This results in 36 ordered pairs. We can take advantage of symmetry through interchanging A with B as follows. Clearly (i,j’) and (j,i’) are equivalent, since interchanging A and B takes us from p to p’ and back. So we can require that i j. Thus we have the following 21 ordered pairs to consider. We need to determine the status of all attributes INF, Al, ALF, FIN, NON, for each pair.
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}