Homework 12-2

Homework 12-2 - 11.24 A B C D E F y hat = 131.92...

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A) y hat = 131.92 + 2.73x1+.05x2-2.59x3 B) sig level 0.01 F 0 Since 2.32E-05 < .01, there is a relationship C) H0 B2=0 H1 B2=/0 sig level 0.05 D) R^2= .770. This is pretty high which means that the independent variables explain part of the total sample variation if y E) y hat = 131.92 + 2.73x1+.05x2-2.59(20) =y hat = 131.92 + 2.73x1+.05x2-51.8 1 pound increase y hat = 131.92 + 2.73x1+.05x2-2.59(21) =y hat = 131.92 + 2.73x1+.05x2-54.39 F) Give a point estimate of the number of hours of labor in a week when 5000 lbs. are shipped, 80% of the units are shipped by truck, and the average shipment y hat = 131.92 + 2.73x1+.05x2-2.59x3 h 0.09 y hat = 131.92 + 2.73(5)+.05(80)-2.59(20) s 9.81 y hat = 131.92 + 13.65 + 4 - 51.8 df 16 y hat 97.77 G) Determine a point estimate of the standard deviation of the model. s 9.81 H) Is there evidence that for each additional pound in the average shipment weight sig level 0.05 Sb3 0.64 df 16 H0 T 1.42 H1 B3 <-3.5 p 0.09 > .05 There is no evidence I) Test the hypothesis that the standard deviaiton of the model is about 12. H0 s=12 df 16 X 484.59 H1 s=/12 y hat 97.77 SSr 46638.48 s 9.81 weight is 20 lbs. The value of h for these inputs is .08766. the hours of labor decreases by less than 3.5 hours?
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Homework 12-2 - 11.24 A B C D E F y hat = 131.92...

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