Stat Homework 11-4

Stat Homework 11-4 - 1) a) At the 5% significance level,...

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1) (in ppm), the sweetness index decreases by about 0.0018. sig level 5% n 24 -0.48 = -0.0018 ρ df 22 p 0.64 -0.0018 ρ ≠ r -0.48 Since p is not equal to -0.0018, we reject the null hypothesis. There is evidence that the sweetness index does not decrease by 0.0018 for every unit increase in pectin b) At the 1% significance level, is there evidence of a relationship between pectin level and sweetness? sig level 1% r -0.48 = 0 μ -2.55 n 24 0 μ ≠ p 0.02 df 22 Since 0.018 is not equal to 0, we can reject the null hypothesis. There is evidence of a relationship between pectin level and sweetness. The point estimate for standard deviation is s We go into excel and use data anaylsis to find the value of s s 44.49 sig level 0.1 xl 12.34 lower 35.83 n 24 xu 33.92 upper 59.41 df 22 43546.49 The 90% confidence interval for the standard deviation will be 35.83, 59.41 0.28? sig level 0.1 s 44.49 We do not continue since 43546.49 s > .28 < 0.28 σ a) At the 5% significance level, test the hypothesis that for every unit increase of pectin
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This note was uploaded on 08/07/2011 for the course STAT 930 taught by Professor Dong during the Fall '10 term at Rutgers.

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Stat Homework 11-4 - 1) a) At the 5% significance level,...

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