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Unformatted text preview: z= 1110/(4/5) z=1/(4/5)= 5/4 z= 0.3944 so 0.50.3944 =0.1056 or approx 11% c. What is the probability that in a random sample of 10 students an average of exactly 10 pizzas are consumed? x=0 Bonus (5 points): Referring to the above problem, what is the probability that each of the students in a randomly drawn sample of 3 consumed more than 12 pizzas for a given month? xbar= 12/4=3 z= 410/(4/sqrt of3) z= 2.6 so 0.4953 then add 0.5 + 0.4953 =0.9953 or approx 99%...
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This note was uploaded on 08/08/2011 for the course WCOB 1033 taught by Professor Jensen during the Fall '05 term at Arkansas.
 Fall '05
 Jensen

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