DataHomework9 - z= 11-10/(4/5) z=1/(4/5)= 5/4 z= 0.3944 so...

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Bryan Redd Homework 9 Due Date: Thursday, February 14th, 2008 by 11:55 p.m. Please Note: show all your work! 1. The number of pizzas consumed per month by university students is normally distributed with a mean of 10 and a standard deviation of 4. a. What proportion of students consume more than 10 pizzas per month? 0.5 or 50% based on picture b. What is the probability that, in a random sample of 25 students, more than 275 pizzas are consumed? (Hint: make sure and think about this one first) xbar=275/25=11 z=xbar-µ/(σ/sqrtof n)
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Unformatted text preview: z= 11-10/(4/5) z=1/(4/5)= 5/4 z= 0.3944 so 0.5-0.3944 =0.1056 or approx 11% c. What is the probability that in a random sample of 10 students an average of exactly 10 pizzas are consumed? x=0 Bonus (5 points): Referring to the above problem, what is the probability that each of the students in a randomly drawn sample of 3 consumed more than 12 pizzas for a given month? xbar= 12/4=3 z= 4-10/(4/sqrt of3) z= 2.6 so 0.4953 then add 0.5 + 0.4953 =0.9953 or approx 99%...
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This note was uploaded on 08/08/2011 for the course WCOB 1033 taught by Professor Jensen during the Fall '05 term at Arkansas.

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