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Modern Digital Electronics- R P Jain- Solution Manual

# Modern Digital Electronics- R P Jain- Solution Manual -...

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R P Jain Solution Manual for Modern Digital Electronics Third Edition

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CHAPTER 1 1.1 (a) Analog. The output of a pressure gauge is proportional to the pressure being measured and can assume any value in the given range. (b) Digital. An electric pulse is produced for every person entering the exhibi- tion using a photoelectric device. These pulses are counted using a digital circuit. (c) Analog. The reading of the thermometer is proportional to the temperature being measured and can assume any value in the given range. (d) Digital. Inputs are given with the help of switches, which are converted into digital signals 1 and 0 corresponding to the switch in the ON or OFF position. These signals are processed using digital circuits and the results are displayed using digital display devices. (e) Analog. It receives modulated signals which are analog in nature. These signals are processed by analog circuits and the output is again in the analog form. (f) Digital. It has only two possible positions (states), ON and OFF. (g) Digital. An electric pulse is produced for every vote cast by pressing of switch of a candidate. The pulses thus produced for each candidate are counted separately and also the total number of votes polled are counted. 1.2 (a) (i) S 1 S 2 Bulb (ii) S 1 S 2 Bulb OFF OFF OFF OFF OFF OFF OFF ON OFF OFF ON ON ON OFF OFF ON OFF ON ON ON ON ON ON ON (iii) S Bulb (iv) S 1 S 2 Bulb OFF ON OFF OFF OFF ON OFF OFF ON ON ON OFF ON ON ON OFF (b) (i) S 1 S 2 Bulb (ii) S 1 S 2 Bulb 0 0 0 0 0 0 0 1 0 0 1 1 1 0 0 1 0 1 1 1 1 1 1 1 (iii) S Bulb (iv) S 1 S 2 Bulb 0 1 0 0 0 1 0 0 1 1 1 0 1 1 1 0 (c) (i) AND (ii) OR (iii) NOT (iv) EX-OR
2 1.3 1.4 Inputs Outputs of A B (a) (b) (c) (d) 0 0 1 1 0 0 0 1 0 1 0 1 1 0 0 1 0 1 1 1 0 0 1 1 The operations performed are (a) NOR (b) NAND (c) AND (d) OR 1 0 1 0 1 0 1 0 1 0 1 0 1 0 0 1 2 3 4 5 t ( ms ) 0 1 2 3 4 5 t ( ms ) Input B AND OR NAND NOR EX-OR Input A

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3 1.5 For Fig. 1.6 (a) A Y (b) A B AB Y 0 1 0 0 1 0 1 0 0 1 1 0 1 0 1 0 1 1 0 1 (c) A B A B Y 0 0 1 1 0 0 1 1 0 1 1 0 0 1 1 1 1 0 0 1 For Fig. 1.8 (a) A Y (b) A B A B + Y 0 1 0 0 1 0 1 0 0 1 0 1 1 0 0 1 1 1 0 1 (c) A B A B Y 0 0 1 1 0 0 1 1 0 0 1 0 0 1 0 1 1 0 0 1 1.6 (a) NAND , NOR (b) AND (c) NAND (d) OR 1.7 (a) Inputs A B A B Output A B Y 0 0 0 0 0 0 1 0 1 1 1 0 1 0 1 1 1 0 0 0 (b) EX OR (c) A B Y
4 (d) Y = AB A B + \ Y = + AB A B = AB AB Y = Y = AB AB = Y Y 1 2 where, Y 1 = AB and Y 2 = AB A B Y Y 1 Y 2 1.8 For simplicity, we shall consider 2-input gates, but the results are equally valid for any number of inputs. In the positive logic system, the higher of the two voltages is designated as 1 and the lower voltage as 0. On the other hand in the negative logic system, the lower of the two voltage is designated as 1 and the higher voltage as 0. Therefore, if 1s and 0s are interchanged, the logic system will change from positive to negative and vice-versa . (a) In the truth table of positive logic AND gate replace all zeros by ones and all ones by zeros. The resulting truth table is same as that of the OR gate. Similarly, if all ones and zeros are interchanged in the truth table of the OR gate, the resulting truth table will be same as that of the AND gate.

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