exam_2_Morning - CHEM 2312 Feb. 16th 2005_ Morning Test...

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1 CHEM 2312 Feb. 16 th 2005_ Morning Test Exam2 NAME: Roll#: Section: . The exam is designed to be completed in 50 minutes or less. This is a closed book exam. The value of each question is denoted by each question. A complete exam requires answers to all 7 questions. PLEASE PUT YOUR NAME/ID ON EACH PAGE 1. Identify which compound is the dominant product for each reaction described below. Place your answer in the corresponding box (total of 12 marks, 4 marks/reaction) Cl O H 3 C O CH 3 O O AlCl 3 H O O CH 3 CH 3 O B1 B2 B3 B4 HN NO 2 HN N C1 C2 C3 C4 HN H NO 2 Cl OH NO 2 NaOH, H 2 O Cl NO 2 OH NO 2 OH D1 D2 D3 D4 O Cl 2 /AlCl 3 O O O Cl Cl Cl B4 C3 D1
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2 CHEM 2312 Feb. 16 th 2005 Exam2 NAME: Roll#: Section: . 2. Circle the letter on the right which corresponds to the answer to each question. There is only one correct answer for each question. (total of 16 marks, 4 marks/question) (i) Which of the following is meta directing substituent on an aromatic ring? E4 E1. -CH 3 E2. –O-CH 3 E3. -(CH 3 ) 3 E4. -C N (ii)
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This note was uploaded on 08/11/2011 for the course CHEM 2312 taught by Professor Baron during the Spring '07 term at Georgia Institute of Technology.

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exam_2_Morning - CHEM 2312 Feb. 16th 2005_ Morning Test...

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