Engineering Mechanics - DynamicsChapter 12vt()b1ec−t−=spt0tt⌠⎮⌡d=spt11.839 m=Problem 12–13 The velocity of a particle traveling in a straight line is given v= bt+ ct2. If s= 0 when t= 0,determine the particle’s deceleration and position when t= t1. How far has the particle traveledduring the time t1, and what is its average speed?Given:b6ms2=c3−ms3=t00s=t13s=Solution:btct2+=attdd=spt0tt⌠⎮⌡d=Deceleration a11=a112−ms2=Find the turning time t2t21.5 s=Given20=t2Findt2=t22s=Total distance traveleddspt1spt2−spt2spt0−+=d8m=Average speedvavespeeddt1t0−=vavespeed2.667ms=Problem 12–14A particle moves along a straight line such that its position is defined by
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