Unformatted text preview: h above the ground. If the elevator can accelerate at a 1 , decelerate at a 2 , and reach a maximum speed v , determine the shortest time to make the lift, starting from rest and ending at rest. Given: h 48 ft = a 1 0.6 ft s 2 = a 2 0.3 ft s 2 = v 8 ft s = Solution: Assume that the elevator never reaches its maximum speed. Guesses t 1 1 s = t 2 2 s = v max 1 ft s = h 1 1 ft = Given v max a 1 t 1 = 9...
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This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.
 Spring '08
 ChristianFeldt
 Dynamics

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