12_Dynamics 11ed Manual - Engineering Mechanics - Dynamics...

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Engineering Mechanics - Dynamics Chapter 12 h 1 1 2 a 1 t 1 2 = 0 v max a 2 t 2 t 1 () = hh 1 v max t 2 t 1 + 1 2 a 2 t 2 t 1 2 = t 1 t 2 v max h 1 Find t 1 t 2 , v max , h 1 , = t 2 21.909 s = Since v max 4.382 ft s = < v 8 ft s = then our original assumption is correct. Problem 12-19 A stone A is dropped from rest down a well, and at time t 1 another stone B is dropped from rest. Determine the distance between the stones at a later time t 2 . Given: d 80 ft = t 1 1s = t 2 2s = g 32.2 ft s 2 = Solution: a A g = v A gt = s A g 2 t 2 = a B g = v B gt t 1 = s B g 2 tt 1 2 = At time t 2 s A2 g 2 t 2 2 = s A2 64.4 ft = s B2
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