15_Dynamics 11ed Manual - Engineering Mechanics - Dynamics...

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Engineering Mechanics - Dynamics Chapter 12 t 0 s p s p 1 2 bs p cs p 2 + d = t 1 0 s p1 s p 1 2 p p 2 + d = t 1 5.624 s = *Problem 12–24 A particle is moving with velocity v 0 when s = 0 and t = 0. If it is subjected to a deceleration of ak v 3 = , where k is a constant, determine its velocity and position as functions of time. Solution: a d v d t = k v 3 = v 0 v v v 3 d 0 t t k d = 1 2 v 2 v 0 2 () k t = vt 1 2 kt 1 v 0 2 + = d sv d t = 0 s s 1 d 0 t t 1 2 1 v 0 2 + d = st 1 k 2 1 v 0 2 + 1 v 0 = Problem 12–25 A particle has an initial speed
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This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.

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