55_Dynamics 11ed Manual - t = t 1 . Also, what is the x , y...

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Engineering Mechanics - Dynamics Chapter 12 Problem 12-66 A particle, originally at rest and located at point ( a , b , c ), is subjected to an acceleration a c = { d t i + e t 2 k }. Determine the particle's position ( x , y , z ) at time t 1 . Given: a 3f t = b 2f t = c 5f t = d 6 ft s 3 = e 12 ft s 4 = t 1 1s = Solution: a x dt = v x d 2 t 2 = s x d 6 t 3 a + = x d 6 t 1 3 a + = x 4ft = a y 0 = v y 0 = s y b = yb = y 2ft = a z et 2 = v z e 3 t 3 = s z e 12 t 4 c + = z e 12 t 1 4 c + = z 6ft = Problem 12-67 The velocity of a particle is given by v = [ at 2 i + bt 3 j + ( ct + d ) k] . If the particle is at the origin when
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Unformatted text preview: t = t 1 . Also, what is the x , y , z coordinate position of the particle at this instant? Given: a 16 m s 3 = b 4 m s 4 = c 5 m s 2 = d 2 m s = t 1 2 s = Solution: Acceleration a x 2 at 1 = a x 64 m s 2 = a y 3 bt 1 2 = a y 48 m s 2 = a z c = a z 5 m s 2 = a mag a x 2 a y 2 + a z 2 + = a mag 80.2 m s 2 = Postition x a 3 t 1 3 = x 42.667 m = y b 4 t 1 4 = y 16 m = 53...
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This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.

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