66_Dynamics 11ed - Engineering Mechanics Dynamics sx = vw t sy = 1 0= Thus 2 1 2 Chapter 12 2 g t vA t h 2 g t vA t h vx = vw t= 2 vA vA 2g h t =

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Engineering Mechanics - Dynamics Chapter 12 s x v w t = s y 1 2 gt 2 v A t + h + = Thus 0 1 2 2 v A t + h + = t v A v A 2 2 gh + + g = t 3.551 s = v x v w = v y g tv A + = vv x 2 v y 2 + = v 32.0 m s = Problem 12-83 Determine the height h on the wall to which the firefighter can project water from the hose, if the angle θ is as specified and the speed of the water at the nozzle is v C . Given: v C 48 ft s = h 1 3f t = d 30 ft = θ 40 deg = g 32.2 ft s 2 = Solution: a x 0 = a y g = v x v C cos ()
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.

Ask a homework question - tutors are online