93_Dynamics 11ed Manual - Engineering Mechanics - Dynamics...

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Engineering Mechanics - Dynamics Chapter 12 Given: v A 0.7 m s = v B 1.5 m s = t 1 2s = ρ 5m = Solution: (a) The displacement along the path s A v A t 1 = s A 1.4 m = s B v B t 1 = s B 3m = (b) The position vector to each particle θ A s A = r A sin A () ρρ cos A () = r A 1.382 0.195 m = B s B = r B sin B () cos B () = r B 2.823 0.873 m = (c) The shortest distance between the particles d r B r A = d 4.26 m = Problem 12-126 The two particles A and
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This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.

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