134_Dynamics 11ed Manual

134_Dynamics 11ed Manual - Engineering Mechanics - Dynamics...

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Engineering Mechanics - Dynamics Chapter 12 Solution: x B d 2 h 2 = Lx C h 2 x B 2 + + = 0 v C x B v B h 2 x B 2 + + = v B v C h 2 x B 2 + x B = v B 6.078 ft s = Positive means to the right, negative to the left. Problem 12-191 The man pulls the boy up to the tree limb C by walking backward. If he starts from rest when x A = 0 and moves backward with constant acceleration a A , determine the speed of the boy at the instant y B = y B1 . Neglect the size of the limb. When x A = 0, y B = h so that A and B are coincident, i.e., the rope is 2 h long. Given: a A 0.2 m s 2 = y B1 4m = h 8m = Solution: y B y B1 = Guesses x A 1m = v A 1 m s = v B 1 m s = Given 2 hx A 2 h 2 + y B + = 0 x A v A x A 2 h 2 + v B + = v A 2 2 a A x A = x
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This note was uploaded on 08/16/2011 for the course EGN 3321 taught by Professor Christianfeldt during the Spring '08 term at University of Central Florida.

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